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3 years ago

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Percy is shopping online and finds a great deal on bookcases. Percy pays $27 for a bookcase that originally sold for $36. What i

s the discount percentage? Write your answer using a percent sign (%).
HELP

1 answer:

Roman55 [17]3 years ago

7 0

Answer:

The answer is $84

Step-by-step explanation:

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The area of a playground is 216 yd^2. The width of the playground is 6 yd longer than its length. Find the length and width of t

zvonat [6]

Let the length of the playground be x, then the width is 6 + x.

Area = length * width = x * (6 + x) = 6x + x^2 = 216

Solving the quadratic equation x^2 + 6x - 216 = 0, we have x = 12 or -18

i.e length = 12 and width = 6 + 18 = 18

5 0

3 years ago

Devin borrowed $1,058 at 13 percent for nine months. What will he pay in interest?

Viktor [21]

Devin borrowed $1,058 at 13 percent for nine months.

We have to calculate the interest paid.

Interest = $\frac{P \times R \times T}{100}$

Substituting the values of

Principal = $1058

Rate = 13%

Time = 9 months = $\frac{9}{12}$ year

Interest = $\frac{1058 \times 13 \times 9}{12 \times 100}$

Interest = 103.155

= 103.16

So, Devin will pay 103.16 as the interest.

Therefore, Option A is the correct answer.

8 0

3 years ago

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Graph the equation <br><br><br> Y=- 1/4x-3

Eduardwww [97]

Answer: Choice #2

Step-by-step explanation: The slope of -1/4 means that the line is ascending to the left, which rules out the first and last choice. The y-intercept of -3 means that it crosses the y-axis at (0,-3). This is why it is #2.

Brainliest please?

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3 years ago

Estimate the value of 196 divided by 0.499

tester [92]

The exact answer would be <span>392.78

An estimated value could be either 390 or 393</span>

4 0

3 years ago

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PLEASE HELP I DO NOT UNDERSTAND AT ALL ITS PRECALC PLEASE SERIOUS ANSWERS

Elina [12.6K]

You want to end up with $A\sin(\omega t+\phi)$ . Expand this using the angle sum identity for sine:

$A\sin(\omega t+\phi)=A\sin(\omega t)\cos\phi+A\cos(\omega t)\sin\phi$

We want this to line up with $2\sin(4\pi t)+5\cos(4\pi t)$ . Right away, we know $\omega=4\pi$ .

We also need to have

$\begin{cases}A\cos\phi=2\\A\sin\phi=5\end{cases}$

Recall that $\sin^2x+\cos^2x=1$ for all $x$ ; this means

$(A\cos\phi)^2+(A\sin\phi)^2=2^2+5^2\implies A^2=29\implies A=\sqrt{29}$

Then

$\begin{cases}\cos\phi=\frac2{\sqrt{29}}\\\sin\phi=\frac5{\sqrt{29}}\end{cases}\implies\tan\phi=\dfrac{\sin\phi}{\cos\phi}=\dfrac52\implies\phi=\tan^{-1}\left(\dfrac52\right)$

So we end up with

$2\sin(4\pi t)+5\cos(4\pi t)=\sqrt{29}\sin\left(4\pi t+\tan^{-1}\left(\dfrac52\right)\right)$

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3 years ago

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