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Bingel [31]
3 years ago
7

How to solve radical numerator fractions

Mathematics
1 answer:
Nonamiya [84]3 years ago
3 0
Y=radical 3
just cancel out the 2 on both sides
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Help me plez guys i need atleast a 67 to play games today
Savatey [412]

Answer:

6/12 and 4/8

Step-by-step explanation:

2/4 = 1/2

___________________

6/8 not equal to 1/2

6/12 = 1/2

4/8 = 1/2

4/6 does not equal to 1/2

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7 0
3 years ago
Can someone help me with 16 and 20? If you’re supposed to write a contrapositive and inverse, but the word not is already in the
Dmitry_Shevchenko [17]
Since 2 'not's cancel out, 16's contrapositive is 'If the light will go on, then the fuse has not blown'. In addition, the inverse would be 'If the fuse has not blown, then the light will go on'. I challenge you to do 20 using this information!
4 0
3 years ago
A.( 18:32)
Vinil7 [7]

Answer:

Step-by-step explanation:

18 in every 32 (people or whatever it is) 18/32 then simplify i believe

4 0
3 years ago
What are the solutions?<br>8x^2-12x-23=-5​
erastova [34]

Answer:

x = 3/4 + (3 sqrt(5))/4 or x = 3/4 - (3 sqrt(5))/4

Step-by-step explanation:

Solve for x over the real numbers:

8 x^2 - 12 x - 23 = -5

Divide both sides by 8:

x^2 - (3 x)/2 - 23/8 = -5/8

Add 23/8 to both sides:

x^2 - (3 x)/2 = 9/4

Add 9/16 to both sides:

x^2 - (3 x)/2 + 9/16 = 45/16

Write the left hand side as a square:

(x - 3/4)^2 = 45/16

Take the square root of both sides:

x - 3/4 = (3 sqrt(5))/4 or x - 3/4 = -(3 sqrt(5))/4

Add 3/4 to both sides:

x = 3/4 + (3 sqrt(5))/4 or x - 3/4 = -(3 sqrt(5))/4

Add 3/4 to both sides:

Answer:  x = 3/4 + (3 sqrt(5))/4 or x = 3/4 - (3 sqrt(5))/4

4 0
3 years ago
12351 rounded to the nearest hundred explain how you rounded
Nataly_w [17]
\bf 12,\underline{351}\impliedby \textit{3 hundreds, and 51 units, let's round that}&#10;\\\\\\&#10;\begin{array}{llll}&#10;300----- 50-----400\\&#10;\qquad \qquad \uparrow\qquad \qquad \qquad \uparrow  \\&#10;&#10;\begin{array}{llll}&#10;anything\ here\\&#10;rounds\ up\ to\\&#10;300&#10;\end{array}\quad&#10;\begin{array}{llll}&#10;anything\ here\\&#10;rounds\ up\ to\\&#10;400&#10;\end{array}&#10;\end{array}&#10;\\\\\\&#10;\textit{therefore, the hundreds value of 300, the 51 tips it over to 400}&#10;\\\\\\&#10;12,\underline{400}
3 0
3 years ago
Read 2 more answers
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