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2 years ago

Question 5 (Multiple Choice Worth 4 points)

Mathematics

1 answer:

Lilit [14]2 years ago

5 0

Answer: ∠p and ∠s, ∠q and ∠r

Step-by-step explanation:

From the lines on the angles indicate which ones are corresponding, for example angles p and s both have 2 lines, while angles q and r both have one line.

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Use the equation below to find c, if a = 43 and b = 49. c=180-a-) ?

Luden [163]

Answer:

Step-by-step explanation:

43 + 49= 92.

Then 180 - 92= 88

C= 88

7 0

3 years ago

Arrange the following number in descending order 0,9; 0,009; 0,09; <br>0,0009 ;9,09

VLD [36.1K]

Answer:

9.09 , 0.9 , 0.09 , 0.009 , 0.0009

Explanation:

The more places behind a decimal point a number is, the smaller it is

Hope this helped you! :)

8 0

2 years ago

If a square is dilated by a factor of 2 what is the measure of each individual angle

vodomira [7]

Answer:

4:1

Step-by-step explanation:

If the side length x is dilated to 2x, the area x² will dilate to (2x)² = 4x², which is 4 times the original x².

6 0

3 years ago

Oil is pumped continuously from a well at a rate proportional to the amount of oil left in the well. Initially there were millio

JulijaS [17]

Answer:

The amount of oil was decreasing at 69300 barrels, yearly

Step-by-step explanation:

Given

$Initial =1\ million$

$6\ years\ later = 500,000$

Required

At what rate did oil decrease when 600000 barrels remain

To do this, we make use of the following notations

t = Time

A = Amount left in the well

So:

$\frac{dA}{dt} = kA$

Where k represents the constant of proportionality

$\frac{dA}{dt} = kA$

Multiply both sides by dt/A

$\frac{dA}{dt} * \frac{dt}{A} = kA * \frac{dt}{A}$

$\frac{dA}{A} = k\ dt$

Integrate both sides

$\int\ {\frac{dA}{A} = \int\ {k\ dt}$

$ln\ A = kt + lnC$

Make A, the subject

$A = Ce^{kt}$

$t = 0\ when\ A =1\ million$ i.e. At initial

So, we have:

$A = Ce^{kt}$

$1000000 = Ce^{k*0}$

$1000000 = Ce^{0}$

$1000000 = C*1$

$1000000 = C$

$C =1000000$

Substitute $C =1000000$ in $A = Ce^{kt}$

$A = 1000000e^{kt}$

To solve for k;

$6\ years\ later = 500,000$

i.e.

$t = 6\ A = 500000$

So:

$500000= 1000000e^{k*6}$

Divide both sides by 1000000

$0.5= e^{k*6}$

Take natural logarithm (ln) of both sides

$ln(0.5) = ln(e^{k*6})$

$ln(0.5) = k*6$

Solve for k

$k = \frac{ln(0.5)}{6}$

$k = \frac{-0.693}{6}$

$k = -0.1155$

Recall that:

$\frac{dA}{dt} = kA$

Where

$\frac{dA}{dt}$ = Rate

So, when

$A = 600000$

The rate is:

$\frac{dA}{dt} = -0.1155 * 600000$

$\frac{dA}{dt} = -69300$

<em>Hence, the amount of oil was decreasing at 69300 barrels, yearly</em>

7 0

2 years ago

Someone please help me !!

wariber [46]

Answer:

B. 56

l hope it is correct or maybe

3 0

3 years ago