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miv72 [106K]
3 years ago
10

Solve the simultaneous equations 2x + y = 5 and 2y = x – 10.

Mathematics
2 answers:
Black_prince [1.1K]3 years ago
7 0
X = 4
The first equation can be substituted into the second one. It would be: 2(-2x+5)=x-10 and after solving it, x = 4
lisov135 [29]3 years ago
7 0

▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ { \huge \mathfrak{Answer}}▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪

The given equations are :

  • 2x + y = 5

  • 2y = x - 10

From the first equation, we get :

  • 2x + y = 5

  • y = 5 - 2x

now, let's put the value of y as (5 - 2x) in second equation to find the value of x :

  • 2y = x - 10

  • 2(5 - 2x) = x - 10

  • 10 - 4x = x - 10

  • 5x = 20

  • x = 4

hence, value of x = 4, Plugging the value of x in second equation :

  • 2y = x - 10

  • 2y = 4 - 10

  • 2y =  - 6

  • y =  - 3

so, the required values are :

  • x = 4

  • y = -3
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4) The path of a satellite orbiting the earth causes it to pass directly over two
Naily [24]

Answers:

  • Satellite is approximately <u>2446.43 km</u> from station A.
  • Satellite is approximately <u>2441.61 km</u> above the ground.

=========================================================

Explanation:

I'm assuming tracking stations A and B are at the same elevation and are on flat ground. In reality, this is likely not the case; however, for the sake of simplicity, we'll assume this is the case.

The diagram is shown below. Points A and B describe the two stations, while point C is the satellite's location. Point D is on the ground directly below the satellite. We have these lengths

  • AB = 60 km
  • AD = x
  • CD = h

Focusing on triangle ACD, we can apply the tangent rule to isolate h.

tan(angle) = opposite/adjacent

tan(A) = CD/AD

tan(86.4) = h/x

x*tan(86.4) = h

h = x*tan(86.4)

We'll use this later in the substitution below.

--------------------

Now move onto triangle BCD. For the reference angle B = 85, we can use the tangent rule to say

tan(angle) = opposite/adjacent

tan(B) = CD/DB

tan(B) = CD/(DA+AB)

tan(85) = h/(x+60)

tan(85)*(x+60) = h

tan(85)*(x+60) = x*tan(86.4) .............  apply substitution; isolate x

x*tan(85)+60*tan(85) = x*tan(86.4)

60*tan(85) = x*tan(86.4)-x*tan(85)

60*tan(85) = x*(tan(86.4)-tan(85))

x*(tan(86.4)-tan(85)) = 60*tan(85)

x = 60*tan(85)/(tan(86.4)-tan(85))

x = 153.612786190499

--------------------

We'll use this approximate x value to find h

h = x*tan(86.4)

h = 153.612786190499*tan(86.4)

h = 2441.60531869599

h = 2441.61 km  is how high the satellite is above the ground.

Return to triangle ACD. We'll use the cosine rule to determine the length of the hypotenuse AC

cos(angle) = adjacent/hypotenuse

cos(A) = AD/AC

cos(86.4) = x/AC

cos(86.4) = 153.612786190499/AC

AC*cos(86.4) = 153.612786190499

AC = 153.612786190499/cos(86.4)

AC = 2446.43279498247

AC = 2446.43 km is the distance from the satellite to station A.

6 0
3 years ago
I will mark you brainiest if you can answer this
Firlakuza [10]

Answer:

D

Step-by-step explanation:

7 0
3 years ago
(05.05)
Bas_tet [7]

Answer:

5

Step-by-step explanation:

The initial value is when x=0

When x=0, y =5

The initial value is 5

3 0
3 years ago
Will mark brainliest has to be correct. ​
yarga [219]
Answer:
x=12
Step by step explanation:

7 0
3 years ago
Please can you help me with questions 1-6
Maru [420]
1.) -4x-32  2.) -6x-3  3.) -3n-28  4.) -2x-7  5.) ???  6.) 4b-2    (I couldn't figure out #5 sorry)
7 0
3 years ago
Read 2 more answers
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