Hi there!
We are given the equation w² + 7w + 12 = 0, and we are told to solve it. Well, we can first take all the factors of 12 -
1 12
2 6
3 4
Now, take the sum of each factor pair -
1, 12 = 13
2, 6 = 8
3, 4 = 7
Find which factor pair adds up to 7, and we can see that 3 and 4 add up to seven, while also having a product of 12. Therefore, since the whole equation has addition signs, we can factor the equation w² + 7w + 12 into (w + 3)(w + 4) = 0. Next, using the Zero Product Property, we can set each term to zero.
w + 3 = 0
w = -3
w + 4 = 0
w = -4
Therefore, the solution to the equation w² + 7w + 12 = 0 is w = -3, -4. Hope this helped and have a great day!
9514 1404 393
Answer:
see below
Step-by-step explanation:
The area of a square is the square of the side length, as shown in the given table.
The area of a circle is pi (π) times the square of the radius. For a radius that is the same as the side length of a square, the circle will have an area π times as large.
For an input of 3, the square area function outputs 9.
For an input of 3, the circle area function outputs 9π, about 28.3.
a/b * b/c * c/d * d/e is equal to a/e provided that b, c, d,
and e are not zero
PROVE
a/b * b/c * c/d * d/e
= (a/b *b/c) * (c/d * d/e)
= ab/bc * (c/d * d/e)
= a/c * (c/d * d/e)
= a/c * (cd/de)
= a/c * c/e
= ac/ce
= a/e
Therefore, a/b * b/c * c/d * d/e is equal to a/e provided that
b, c, d, and e are not zero
Diagonal of a square is √2a
so,
√2 a = 12
a= 12/√2
and.. perimeter of a square is 4a
so,
peri = 4*12/√2
= 48/√2
=33.94cm
Answer:
There is no table
Step-by-step explanation:
But to construct a histogram, we use frequence on the y-axis and class boundaries on the x-axis
