So assuming L=legnth
xd=y(L-d)
divide both sides by y
(xd)/y=L-d
add d to both sides
((xd)/y)+d=L
Answer:
A) 
B) 
C) 
D)
Step-by-step explanation:
Hope this helps.
For there to be 1 car, we consider two possible outcomes:
The first door opened has a car or the second door opened has a car.
P(1 car) = 2/6 x 4/5 + 4/6 x 2/5
P(1 car) = 8/15
For there to be no car in either door
P(no car) = 4/6 x 3/5
P(no car) = 2/5
Probability of at least one car is the sum of the probability of one car and probability of two cars:
P(2 cars) = 2/6 x 1/5
= 1/15
P(1 car) + P(2 cars) = 8/15 + 1/15
= 3/5
Answer:
80
Step-by-step explanation:
the 80 is the tenth part so you do nothing its a trip up qustion
Answer:
She has $20 + $0.50n in her tip jar.
Step-by-step explanation:
Amount in tip jar at noon = $20
Average amount made from each customer = $0.50
Number of additional customers served after noon = n
Therefore, we have:
Additional amount made after noon = Average amount made from each customer * Number of additional customers served after noon = $0.50 * n = $0.50n
Amount in tip jar = Amount in tip jar at noon + Additional amount made after noon = $20 + $0.50n
Therefore, she has $20 + $0.50n in her tip jar.
