A - 3b = 4 . . . . (1)
a = b - 2 . . . . . (2)
Putting (2) into (1), we have
b - 2 - 3b = 4
-2b = 4 + 2 = 6
b = 6/-2 = -3
From (1), a = b - 2 = -3 - 2 = -5
Hence, solution = (-5, -3)
The three angles are 45, 75, and 60. The sides across from these angles correspond to the length of the sides. Since 45 < 60 < 75, MN < ON < MO. The answer is therefore C. MN, ON, MO.
Hope this helps!
Answer:
Step-by-step explanation:
9(5 + 2)
the answer is D
The answer is 345 :) hope this helps u
Answer:
Yes, there are infinite triangles with the same three angles but different side lengths
Step-by-step explanation:
we know that
If two triangles are similar, then the ratio of its corresponding sides is proportional and its corresponding angles are congruent
therefore
There are infinite triangles with the same three angles but different side lengths
