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irinina [24]
3 years ago
8

I've got a q: An airplane touches down on the runway with a speed of 70 m/s. It decelerates at a rate of -5 m/s 2. Determine the

speed of the airplane after each second (which is 1234 seconds)
of its deceleration. PLZ help meh
Mathematics
1 answer:
Helga [31]3 years ago
3 0
After 1 sec it would be 65 m/s
after 2 sec it would be 55 m/s
after 3 sec it would be 40 m/s
after 4 sec it would be 20 m/s
and so on. The equation for this is
S = 70 - (-5(t)) where s=speed and t=time passed
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Step by Step Explanation:

Add: 8/

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+ 10/

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= 82/

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= 2 · 41/

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= 41/

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For adding, subtracting, and comparing fractions, it is suitable to adjust both fractions to a common (equal, identical) denominator. The common denominator you can calculate as the least common multiple of both denominators - LCM(10, 9) = 90. In practice, it is enough to find the common denominator (not necessarily the lowest) by multiplying the denominators: 10 × 9 = 90. In the following intermediate step, cancel by a common factor of 2 gives 41/

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In other words - eight tenths plus one ninth = forty-one forty-fifths.

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