Answer:
0.375 or 3/8 you welcome
Step-by-step explanation:
Answer: APBQ : APBC=4:21 and AAQP : AABC= 3:28.
Explanation: given : Here ABC is a triangle where AP:PC=1:3
let AP=1x and PC=3x, where x is the common value of AP and PC.
And AQ:QB = 3:4, similarly, let AQ=3y and QB= 4y, where y is the common value of AQ and QB.
Thus, AC= AP+PC= 1x+3x=4x and AB= AQ+QB= 3y+4y=7y
since, we have to find out APBQ : APBC= AP×BQ: AB×PC= 1x×4y: 7y×3x=4xy:21xy=4:21
So, APBQ : APBC=4:21
Now, AAQP : AABC= AQ×AP:AB×AC= 3y×1x:7y×4x=3xy:28xy=3:28
Thus, AAQP : AABC= 3:28.
Answer:
Manuel's argument is correct. Paul used the incirrect base area to find the volume of square pyramid X
Step-by-step explanation:
step 1
Find the volume of the cone W
we know that
The volume of the cone if given by the formula
we have
substitute the given values
assume
substitute
step 2
Find the volume of the square pyramid
we know that
The volume of the pyramid is given by the formula
where
B is the area of the base
h is the height of pyramid
In this problem we have that
----> is the same that the area of the base of cone
so
----> is the same that the height of the cone
so
substitute
therefore
Manuel's argument is correct. Paul used the incirrect base area to find the volume of square pyramid X
Y is being multiplied by 0.6 so you have to divide by 0.6 on both sides to leave y alone.
y=10.3/0.6
Answer
148cm^2
Explanation
A cuboid has equal width and length as it’s base is a square. So w or l = root 30
Since the volume of a cuboid is
Length • width • height
And we know length and width when multiplied are 30
30 • height = 120
Therefore height = 4
Now for surface area it’s
2 • h • l + 2 • h • w + 2 • l • w
2 • 4 • root 30 + 2 • 4 • root30 + 2 • 30 = 60 + 16root30 = 148~cm^2
