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mario62 [17]
3 years ago
12

Identify the series as geometric or arithmetic. 2, 4/3, 8/9, 16/27

Mathematics
1 answer:
Aleks04 [339]3 years ago
8 0
Hello,

\dfrac{\frac{4}{3}}{2}=\dfrac{4}{6}=\dfrac{2}{3}

\dfrac{\frac{8}{9}}{\frac{4}{3}}=\dfrac{8*3}{9*4}=\dfrac{2}{3}

\dfrac{\frac{16}{27}}{\frac{8}{9}}=\dfrac{16*9}{27*8}=\dfrac{2}{3}

The sequence is geometric .
(a serie is a sum)





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I need help with this practice I am having a tough time solving it properly
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Given:

There are given that the parent functions as a cosine function:

Where,

The amplitude of the function is 9.

The vertical shift is 11 units down.

Explanation:

To find the cosine function, we need to see the standard form of the cosine function:

f(x)=acos(bx+c)+d

Where,

a is the amplitude of the function,

Now,

According to the question:

The amplitude of the function is 9, which means:

f(x)=9cos(bx+c)+d

The vertical shift is 11 units down, which means:

f(x)=9cos(bx+c)-11

For period:

\begin{gathered} f(x)=-9cos(\frac{12\pi}{7}x+0)-11 \\ f(x)=-9cos(\frac{12\pi}{7}x)-11 \end{gathered}

Final answer:

Hence, the cosine function is shown below;

f(x)=-9cos(\frac{12\pi}{7}x)-11

4 0
1 year ago
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swat32
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8 0
3 years ago
Find the complement of the angle shown
Archy [21]
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Answer:

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Since x =  sum of money invested in corporate bonds

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4 0
3 years ago
1. What is the slope of a line that passses through (-1,-5) and (6, 8)?
elena-s [515]

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4 0
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