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stira [4]
3 years ago
8

Why is it important to identify the presence of fecal contamination in the enviorment?

Biology
1 answer:
Brilliant_brown [7]3 years ago
5 0
<span>Fecal matter is the harbor of coliform bacteria. Coliform bacteria are found in the digestive system of warm blooded animals and come out through the fecal matter. It will contaminate the water sources and cause water born diseases like nausea, vomiting, diarrhea, and stomach cramps.</span>
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Which cellular structure makes it possible for a cell to differ structurally and biochemically from its surroundings? select one
icang [17]
Do you have any options?
8 0
3 years ago
By adding the tin atoms to copper, it makes the metal harder to<br><br><br> Helpp??
katovenus [111]

Answer:

Adding tin to copper during melting changes the properties of the metal. The larger tin atoms restrict the movement of the copper atoms, making the material harder.

Explanation:

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7 0
3 years ago
What property of water allows fish to survive in a lake that is frozen over?
Fiesta28 [93]

C. Ice is less dense than water which means water condenses when it freezes allowing the ice in a lake to float on top of the water preventing the water below from freezing.
4 0
3 years ago
A species of frog has inhabited the tropical rain forests of south america for the
kobusy [5.1K]

Answer:

Option B. makes the most sense.

5 0
2 years ago
A population of 150 individuals has an allele frequency of 0.2 for the dominant allele (H) and a frequency of 0.8 for the recess
Amanda [17]
Hardy-Weinberg Equation (HW) states that following certain biological tenets or requirements, the total frequency of all homozygous dominant alleles (p) and the total frequency of all homozygous recessive alleles (q) for a gene, account for the total # of alleles for that gene in that HW population, which is 100% or 1.00 as a decimel. So in short: p + q = 1, and additionally (p+q)^2 = 1^2, or 1
So (p+q)(p+q) algebraically works out to p^2 + 2pq + q^2 = 1, where p^2 = genotype frequency of homozygous dominant individuals, 2pq = genotype frequency of heterozygous individuals, and q^2 = genotype frequency of homozygous recessive individuals.
The problem states that Ptotal = 150 individuals, H frequency (p) = 0.2, and h frequency (q) = 0.8.
So homozygous dominant individuals (HH) = p^2 = (0.2)^2 = 0.04 or 4% of 150 --> 6 people
Heterozygous individuals (Hh) = 2pq = 2(0.2)(0.8) = 0.32 or 32% of 150
--> 48 people
And homozygous recessive individuals (hh) = q^2 = (0.8)^2 = 0.64 = 64% of 150 --> 96 people
Hope that helps you to understand how to solve these types of population genetics problems!
6 0
3 years ago
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