Answer:
A. VG = 80
B. Broad sense heritability = 0.80
C. Narrow sense heritability = 0.30
D. Average yield = 430 Units
Explanation:
A. Given that
VA = 30
VD = 50
VI = assumed not available
Therefore
Total genetic variance (VG) = VA + VD
= 30 + 50
= 80
VG = 80
B. Given that
VP = 100
VG = 80
Broad sense heritability, H2 = VG/VP
= 80/100
= 0.80
C. Given that
VA = 30
VP = 100
Narrow sense heritability, h2 = VA/VP
=30/100
= 0.30
D. The difference in selection = 500 - 400
= 100
Recall,
Selection response is heritability multiplied by selection differential.
That is
R = h2S
Selection differential = 100
Heritability h2 = 0.30
Selection response = 0.30 × 100
= 30units
Therefore, expected average yield = 400 + 30
= 430 Units
Answer:
radioactivity will not be able to tell the difference between the DNA and proteins
Explanation:
It seems that the experiment will fail to show what Hershey and Chase showed because they modify some of the aspects. These modifications will cause changes to the results, the main one being that radioactivity will not be able to tell the difference between the DNA and proteins. This is because Amino Acids are proteins that also contain nitrogen atoms, thus labeling the nitrogen would include all DNA and proteins. This being the main reason why Hershey and Chase decided to label the DNA instead.
Explanation:
In the process of photosynthesis, plants that contain chlorophyll utilize carbon dioxide and water using energy from sunlight that is absorbed by chlorophyll to make glucose + oxygen.
Answer:
Meiosis takes place in germ line cell.
Invovled in reproduction.
Explanation:
They contain high protein, starch and oil reserves that help in the early stages of growth and development in a plant.
