Answer:
Area of the shaded region = 1.92 cm²
Step-by-step explanation:
From the picture attached,
Area of the shaded region = Area of the sector OMN - Area of the triangle OMN
Area of sector OMN = 
Here, θ = Central angle of the sector
r = radius of the sector
Area of sector OMN = 
= 15.708 square cm
Area of ΔOMN = 2(ΔOPN)
Area of ΔOPN = 
Area of ΔOMN = OP × PN
In ΔOPN,
sin(25°) = 
PN = ONsin(25°)
= 6sin(25°)
= 2.536 cm²
cos(25°) = 
OP = ONcos(25°)
OP = 6cos(25°)
OP = 5.438 cm
Area of ΔOMN = 2.536 × 5.438
= 13.791 cm²
Area of the shaded region = 15.708 - 13.791 = 1.917 cm²
≈ 1.92 cm²
Answer:
x=10,y=5,z=2
Step-by-step explanation:
x+15=2x+5
x=10
4y=8y-20
4y=20
y=5
10z-5=3z+9
7z=14
z=2
A function is called linear if highest degree of the equation is 1.
Here, degree of x and y is 1 hence it's a linear function.
<em>3/8 divided by 1/8 = 3</em> Each student must fill the tablespoon 3 times
<em>3 times 4 = 12 </em>Multiplied by four (because there are 4 students) to get total number of times needed to fill the measuring spoon
The group must fill the 1/8 tsp 12 times in order to perform the expirement
if B is the midpoint of AC, that means that B cuts AC in two equal halves, namely that AB and BC are identical twins.
![\bf \boxed{A}\stackrel{4x - 2}{\rule[0.35em]{10em}{0.25pt}} B\stackrel{2x+4}{\rule[0.35em]{10em}{0.25pt}}\boxed{C} \\\\\\ 4x - 2 = 2x + 4\implies 2x-2=4\implies 2x = 6\implies x=\cfrac{6}{2}\implies x = 3 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{AB~=~BC}{4(3)-2= \underline{10}}~\hfill \stackrel{AC = AB+BC}{\underline{10}+\underline{10}=20}](https://tex.z-dn.net/?f=%5Cbf%20%5Cboxed%7BA%7D%5Cstackrel%7B4x%20-%202%7D%7B%5Crule%5B0.35em%5D%7B10em%7D%7B0.25pt%7D%7D%20B%5Cstackrel%7B2x%2B4%7D%7B%5Crule%5B0.35em%5D%7B10em%7D%7B0.25pt%7D%7D%5Cboxed%7BC%7D%20%5C%5C%5C%5C%5C%5C%204x%20-%202%20%3D%202x%20%2B%204%5Cimplies%202x-2%3D4%5Cimplies%202x%20%3D%206%5Cimplies%20x%3D%5Ccfrac%7B6%7D%7B2%7D%5Cimplies%20x%20%3D%203%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7BAB~%3D~BC%7D%7B4%283%29-2%3D%20%5Cunderline%7B10%7D%7D~%5Chfill%20%5Cstackrel%7BAC%20%3D%20AB%2BBC%7D%7B%5Cunderline%7B10%7D%2B%5Cunderline%7B10%7D%3D20%7D)