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maks197457 [2]
3 years ago
6

Find the area under the standard normal distribution curve for the following intervals. a. Between z = 0 and z = 2.0 b. To the r

ight of z = 1.5 c. To the left of z = −1.75 d. Between z = −2.78 and z = 1.66
Mathematics
1 answer:
vesna_86 [32]3 years ago
5 0

Answer:

a) P(0

And we can use the following excel code to find the probability:

"=NORM.DIST(2,0,1,TRUE)-NORM.DIST(0,0,1,TRUE)"

P(0

b) P(Z>1.5) =1-P(Z

And we can use the following code and we got:

"=1-NORM.DIST(1.5,0,1,TRUE)"

P(Z>1.5) =1-P(Z

c) P(z

And we can use the following code and we got:

"=NORM.DIST(-1.75,0,1,TRUE)"

P(z

d) P(-2.78

And we can use the following excel code to find the probability:

"=NORM.DIST(1.66,0,1,TRUE)-NORM.DIST(-2.78,0,1,TRUE)"

P(-2.78

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Part a

We want this probability:

P(0

And we can use the following excel code to find the probability:

"=NORM.DIST(2,0,1,TRUE)-NORM.DIST(0,0,1,TRUE)"

P(0

Part b

For this case we want this probability:

P(Z>1.5)

And we can use the complement rule and we have:

P(Z>1.5) =1-P(Z

And we can use the following code and we got:

"=1-NORM.DIST(1.5,0,1,TRUE)"

P(Z>1.5) =1-P(Z

Part c

We want this probability:

P(z

And we can use the following code and we got:

"=NORM.DIST(-1.75,0,1,TRUE)"

P(z

Part d

We want this probability:

P(-2.78

And we can use the following excel code to find the probability:

"=NORM.DIST(1.66,0,1,TRUE)-NORM.DIST(-2.78,0,1,TRUE)"

P(-2.78

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