Hello!
Answer:
12(3+4+5+...+12+13)= 1,056
Step-by-step explanation:
After evaluating the expression it gave me : 1,056
Hope this helps!
Answer:
16Km due east of school P
Step-by-step explanation:
Given
A school P is 16km due west of a school Q
Thus, we can say that distance PQ = 16 km.
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now we have to find the bearing of Q from P
As distance is same
distance PQ = distance QP
Thus,
Distance will remain same of 16 km.
For direction,
If Q is west of P, then P will be east of Q
as shown in figure P is west of Q,
now from point P , Q is west P.
Thus,
Bearing of School Q from P is 16Km due east of school P
Answer:
Type II error
Step-by-step explanation:
According to the definition of type II error, the type II error arises when we wrongfully accept the null hypothesis. It means that when we accept our null hypothesis and null hypothesis is not correct then type II error arises. So according to situation we are accepting the null hypothesis that the food is safe but it is actually not safe. Hence the given situation represents type II error.
1. 3 + 6 + 9 = 18
18/3 = 6 --> The average is 6
2. 15 + 5 + 8 + 4 = 32
32/4 = 8 --> The average is 8
3. 6 + 10 + 5 = 21
21/3 = 7 --> The average is 7
4. 14 + 9 + 7 = 30
30/3 = 10 --> The average is 10
Point slope form again
-3-9/3+1= -3
y+1=-3(x-9)
y+1=-3x+27
y=-3x+26
5+1/2+1=2
y+1=2(x+1)
y+1=2x+2
y=2x+1
For your system of equations you have
y={y=-3x+26}
y={y=2x+1}
There is a couple ways you can solve this. You could either use a subtraction method, or a substitution method. since they are both y = something i would just substitute one y in one or the other equation.
2x+1=-3x+26
5x+1=26
5x=25
x=5
So now you just plug in x = 5 for each quotation and you have your y's for both solution points
y=-3(5)+26
y=11
y=2(5)+1
y=11
So this works out nice, your solutions for the set of equations is (5,11) since they are the same points
