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4 years ago

7

A spinner is divided into 8 equal sections, and each section contains a number from 1 to 8. What is the probability of the spinn

er landing on 5?
A: 1/13
B:1/8
C: 5/13
D:5/8

1 answer:

nexus9112 [7]4 years ago

6 0

Answer:

b

Step-by-step explanation:

5 is one of the numbers in 1,2,3,4,5,6,7,8

^

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a. Fill in the midpoint of each class in the column provided. b. Enter the midpoints in L1 and the frequencies in L2, and use 1-

Tresset [83]

Answer:

$\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1} & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7} & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}$

Using the frequency distribution, I found the mean height to be 70.2903 with a standard deviation of 3.5795

Step-by-step explanation:

Given

See attachment for class

Solving (a): Fill the midpoint of each class.

Midpoint (M) is calculated as:

$M = \frac{1}{2}(Lower + Upper)$

Where

$Lower \to$ Lower class interval

$Upper \to$ Upper class interval

So, we have:

Class 63-65:

$M = \frac{1}{2}(63 + 65) = 64$

Class 66 - 68:

$M = \frac{1}{2}(66 + 68) = 67$

When the computation is completed, the frequency distribution will be:

$\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1} & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7} & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}$

Solving (b): Mean and standard deviation using 1-VarStats

Using 1-VarStats, the solution is:

$\bar x = 70.2903$

$\sigma = 3.5795$

<em>See attachment for result of 1-VarStats</em>

8 0

3 years ago

Ratios that are equivalent to 7: 6.

Alex

Step-by-step explanation:

21:18=7:6

42:36=7:6

63:54=7:6

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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3 years ago

How many grams equal a quarter pounder

LekaFEV [45]

Answer:

About 113

Step-by-step explanation:

Well, there are about 453 grams in a pound.

So divide 453 by 4, and there's the answer!

453 / 4 ≈ 113

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3 years ago

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