Question

Last question! I need help with showing my work! I already have the answer in the attached image below, thanks!

Answer 1

Answer:

see explanation

Step-by-step explanation:

Given

$\sqrt{\frac{4x^2}{3y} }$

= $\frac{\sqrt{4x^2} }{\sqrt{3y} }$

= $\frac{2x}{\sqrt{3y} }$

Rationalise the denominator by multiplying the numerator/ denominator by $\sqrt{3y}$

Note that $\sqrt{a}$ × $\sqrt{a}$ = a

= $\frac{2x}{\sqrt{3y} }$ × $\frac{\sqrt{3y} }{\sqrt{3y} }$

= $\frac{2x\sqrt{3y} }{3y}$