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s344n2d4d5 [400]
4 years ago
6

Factor the expression X^2 + 6x + 8

Mathematics
1 answer:
zubka84 [21]4 years ago
3 0

Answer: (x + 4)(x + 2)

Step-by-step explanation: In this problem, we're given a trinomial with an x² term, an x term, and a constant term so we can factor it as the product of two binomials.

The first term in each binomial will be a factor of x² and since x² factors as x time x, we use x as the first term in each binomial.

To fill the second position in each binomial, we use the factors of the last term that add together to equal the coefficient of the middle term.

So we're looking for factors of +8 that add to +6.

+8 factors as 8 x 1 or 4 x 2. Since 4 and 2 add together to equal +6, we put a +4 in our first binomial and a +2 in our second binomial and we have our answer (x + 4)(x + 2) which is a factored version of x² + 6x + 8.

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Solve 4x + 11 = k for x. <br> O A. x= -11 <br> O B. x=-11 <br> O C. x = 4k - 44 <br><br> D. x= k-7
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3 years ago
Eric throws a biased coin 10 times. He gets 3 tails. Sue throw the same coin 50 times. She gets 20 tails. Aadi is going to throw
iren2701 [21]

Answer:

(1) The correct option is (A).

(2) The probability that Aadi will get Tails is \frac{2}{5}.

Step-by-step explanation:

It is provided that:

  • Eric throws a biased coin 10 times. He gets 3 tails.
  • Sue throw the same coin 50 times. She gets 20 tails.

The probability of tail in both cases is:

  • P(\text{Tail})=\frac{3}{10}
  • P(\text{Tail})=\frac{20}{50}=\frac{2}{5}

(1)

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

In this case we need to compute the proportion of tails.

Then according to the Central limit theorem, Sue's estimate is best because she throws it <em>n = </em>50 > 30 times.

Thus, the correct option is (A).

(2)

As explained in the first part that Sue's estimate is best for getting a tail, the probability that Aadi will get Tails when he tosses the coin once is:

P(\text{Tail})=\frac{20}{50}=\frac{2}{5}

Thus, the probability that Aadi will get Tails is \frac{2}{5}.

7 0
4 years ago
Read 2 more answers
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