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serg [7]
3 years ago
6

The average 10 year old boy is 55 inches tall. How tall is this, in feet?

Mathematics
1 answer:
Elena L [17]3 years ago
4 0
There is 12 inches in a foot. Times inches by feet. You can pick a number for the feet and do trial and error until you get a number the closet to 55.

12 inches times 4 feet equals 48 inches.
12x4= 48
Now subtract 55 inches from 48 inches
55-48= 7 inches

So 4 feet and 7 inches tall
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MrMuchimi
The next number in the sequence should be 333.111
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The concession stand at a ballpark makes $0.43 profit from each hot dog sold. It also makes a profit of $0.65 from each pretzel
kaheart [24]
0.43h + 0.65p + 1.31d = c

explanation:
h stands for hotdogs, p for pretzels, and d for drinks. c represents the total cost. 
each price next to the variable describes the profit per item.

hope this helps! :D
4 0
3 years ago
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Jared has some quarters and dimes that total $5.50. If he has 8 more quarters that dimes, how much dimes does Jared have?
MAXImum [283]
Answer: 10 dimes

Solve using system of equations.
q=number of quarters and d=number of dimes
.25q+.10d=5.50 because the total of dimes and quarters is $5.50
8+d=q because there are 8 more quarters than dimes
substitute 8+d for q into the first equation to get .25(8+d)+.10d=5.50
then simplify
2+.35d=5.50
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8 0
3 years ago
The Pacific halibut fishery has been modeled by the differential equation dy dt = ky 1 − y K where y(t) is the biomass (the tota
Dafna1 [17]

Answer:

a. The biomass weighs 2.30 * 10^7 kg after a year

b. It'll take 2.56 years to get to 4*10^7kg

Step-by-step explanation:

a.

k = 0.78,K = 6E7 kg

Given

dy/dt = ky(1- y/K)

Make ky dt the subject of formula

ky dt = dy/(1-y/K) --- make k dt the subject of formula

k dt = dy/(y(1-y/K))

k dt = K dy / y(K-y)

k dt = ((1/y) + (1/(K-y)))dy ---- integrate both sides

kt + c = ln(y/(K-y))

Ce^(kt) = y/(K-y)

Substitute the values of k and K

Ce^(0.78t) = y/(6*10^7 - y) ----- (1)

Given that y(0) = 2 * 10^7kg

(1) becomes

Ce^(0.78*0) = (2 * 10^7)/(6*10^7 - 2*10^7)

Ce° = (2*10^7)/(4*10^7

C = 2/7

Substitute 2/7 for C in (1)

2/7e^0.78t = y/(6*10^7 - y) ---(2)

We're to find the biomass a year later

So, t = 1

2/7e^0.78 = y/(6*10^7 - y)

0.62 = y/(6*10^7 - y)

y = 0.62(6*10^7 - y)

y = 0.62*6*10^7 - 0.62y

y + 0.62y = 0.62*6*10^7

1.62y = 0.62*6*10^7

1.62y = 3.72 * 10^7

y = 2.30 * 10^7kg.

Hence, the biomass weighs 2.30 * 10^7 kg after a year

b.

Here, we're to calculate the time it'll take the biomass to get to 4*10^7 kg

Substitute 4*10^7 for y in (2)

2/7e^0.78t = 4*10^7/(6*10^7 - 4*10^7)

2/7e^0.78t = 4*10^7/2*10^7

2/7e^0.78t = 2

e^0.78t = (2*7)/2

e^0.78t = 2

t = 2 * 1/0.78

t = 2.56 years

Hence, it'll take 2.56 years to get to 4*10^7kg

8 0
3 years ago
The figure below is made up of two rectangles.
Dmitry [639]

Answer:

Total area of figure = [3x² + 7x + 6] feet²

Step-by-step explanation:

By dividing both rectangle by vertical line;

Given:

Length of big rectangle = (x + 3) feet

Width of big rectangle = (x + 2) feet

Length of small rectangle = 2x feet

Width of small rectangle = (x + 1) feet

Find:

Total area of figure

Computation:

Area of rectangle = Length x width

Total area of figure = Area of big rectangle + Area of small rectangle

Total area of figure = [(x + 3)(x + 2)] + [(2x)(x + 1)]

Total area of figure = [x²+ 2x + 3x + 6] + [2x² + 2x]

Total area of figure = [3x² + 7x + 6] feet²

7 0
2 years ago
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