Answer:

Step-by-step explanation:
The general form of the quadratic equation is

You are given the quadratic equation

It can be rewritten in standard form as

Hence,

The answer would be multiplies by 1/3
Step-by-step explanation:
Okay, so...
The Median of a trapezoid is directly in the middle. For some weird mathimatical reason you won't ever need to know unless it's on an exam or you become a math major, its midsegment is the average of the top length and the bottom length.
In other words,
EF = ( BC + AD ) / 2
So for part 1, we can use that equation to find x.

![4x-18=[(x+12)+(3x-4)]/2](https://tex.z-dn.net/?f=4x-18%3D%5B%28x%2B12%29%2B%283x-4%29%5D%2F2)
- Simplify within parentheses.
![4x-18=[x+12+3x-4]/2](https://tex.z-dn.net/?f=4x-18%3D%5Bx%2B12%2B3x-4%5D%2F2)
![4x-18=[x+3x+12-4]/2](https://tex.z-dn.net/?f=4x-18%3D%5Bx%2B3x%2B12-4%5D%2F2)
![4x-18=[4x+8]/2](https://tex.z-dn.net/?f=4x-18%3D%5B4x%2B8%5D%2F2)




Part 2 is a lot easier now. All we have to do is plug in 11 for x.



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Answer:
Part I: x = 11
Part II:
Answer:
1041
Step-by-step explanation:
Among the numbers 1–1000, there are 31 squares, so the sequence will extend to at least 1031. In those added numbers, there is another square (1024), so the sequence must extend to at least 1032.
There are 7 more numbers that are cubes, but not squares, so the sequence must extend to at least 1039.
And there are 2 additional numbers that are 5th powers that are not squares or cubes. Compensating for the removal of these numbers extends the end of the sequence to 1041.
There are no numbers in this range that are both cubes and 5th powers and that have not already been accounted for. (The only 15th power is 1.)
Hence, the 1000th number in the sequence is 1041.
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This result is verified by a computer program that listed the numbers.