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Anna71 [15]
3 years ago
12

A small town's raffle has 85 entries and 3 gift baskets that three different people could win. What is the probability of winnin

g a gift basket if you have 1 of the entries
Mathematics
1 answer:
mr_godi [17]3 years ago
5 0

Answer:

<h2>0.035</h2>

Step-by-step explanation:

This problem is on probabilty since there are a number of entries to be selected from which are 85 entries, the chances of winning one of the prices if selected is

the number of entries you have/ total number of entries

given that the total entry is 85

and that you have one entry

Since there are three gift baskets you have three chances to win one.

hence there will be a total of three draws, and after each draw, there won't be a replacement of the previous winner (as the winners are three distinct persons).

Hence the probability of winning a draw for the gift basket is  

=1st draw+2nd draw+3rd draw

= 1/85+1/84+1/83

= 0.0117+0.0119+0.012

= 0.035

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Answer:

a=\dfrac{1}{2}\\ \\b=-3\\ \\c=0

Step-by-step explanation:

The general form of the quadratic equation is

ax^2+bx+c=0

You are given the quadratic equation

0=\dfrac{1}{2}x^2-3x

It can be rewritten in standard form as

\dfrac{1}{2}x^2-3x=0

Hence,

a=\dfrac{1}{2}\\ \\b=-3\\ \\c=0

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Ef is the median of trapezoid abcd (please explain the answer im so confused lol)
Art [367]

Step-by-step explanation:

Okay, so...

The Median of a trapezoid is directly in the middle. For some weird mathimatical reason you won't ever need to know unless it's on an exam or you become a math major, its midsegment is the average of the top length and the bottom length.

In other words,

EF = ( BC + AD ) / 2

So for part 1, we can use that equation to find x.

EF = ( BC + AD ) / 2

  • Insert known equations.

4x-18=[(x+12)+(3x-4)]/2

  • Simplify within parentheses.

4x-18=[x+12+3x-4]/2

4x-18=[x+3x+12-4]/2

  • Add.

4x-18=[4x+8]/2

  • Divide.

4x-18=2x+4

  • Simplify.

(4x-2x) +(-18+18)=(2x-2x)+(4+18)

2x=22

  • Divide both sides by 2.

x=11

Part 2 is a lot easier now. All we have to do is plug in 11 for x.

BC =x+12

BC = 11+12

BC = 23

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AD = 4x-18

AD = 4(11)-18

AD = 44-18

AD = 26

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EF = 3x-4

EF = 3(11)-4

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Answer:

Part I: x = 11

Part II:

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Answer:

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Among the numbers 1–1000, there are 31 squares, so the sequence will extend to at least 1031. In those added numbers, there is another square (1024), so the sequence must extend to at least 1032.

There are 7 more numbers that are cubes, but not squares, so the sequence must extend to at least 1039.

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There are no numbers in this range that are both cubes and 5th powers and that have not already been accounted for. (The only 15th power is 1.)

Hence, the 1000th number in the sequence is 1041.

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This result is verified by a computer program that listed the numbers.

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