Perpendicular lines refers to a pair of straight lines that intercept each other. The slopes of this lines are opposite reciprocal, meaning that it's multiplication is -1.
On this case they give you the equation of a line and a point, and is asked to find the equation of a line that is perpendicular to the given one, and that passes through this point.
-2x+3y=-6 Add 2x in both sides
3y=2x-6 Divide by 3 in both sides to isolate y
y=2/3x-6/3
The slope of the given line is 2/3, which means that the slope of a line perpendicular to this one, needs to be -3/2. Now you need to find the value of b or the y-intercept by substituting the given point into the formula y=mx+b, where letter m represents the slope.
y=mx+b Substitute the given point and the previous slope found
-2=(-3/2)(6)+b Combine like terms
-2=-9+b Add 9 in both sides to isolate b
7=b
The equation that represents the line perpendicular to -2x+3y=-6 and that passes through the point (6,-2), is y=-3/2x+7.
I guess you want the missing angle.
The missing angle is 83
The equation for a circle is
(x-h)^2 + (y-k)^2 = r^2
(-3,6)
-3 is h
6 is k
(x+3)^2 + (y-6)^2 = 10^2
10^2 = 100
(x+3)^2 + (y-6)^2 =100
The answer is B!
Answer:
You have its E because if it's a A percentage you have to turn the inter despara point
