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SIZIF [17.4K]
4 years ago
13

Right now I have in front of me x-6 there's a fraction bar and below it you have 4 and on the side you have >2 how would you

solve this?
Mathematics
1 answer:
Strike441 [17]4 years ago
7 0
If you right it out and solve left to right that should be your answer

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[X + y] + 3w? Helpppppp
lana [24]

Answer:

x+y+3w

Step-by-step explanation:

7 0
3 years ago
If you have a right triangle is 10 cm² and one of the legs is 4 cm find the length of the other leg
lesya [120]

If you are saying that the hypotenuse is 10 cm the you have to solve the following equation using the Pythagorean theory.

4^2 + b^2 = 10^2

16 + b^2 = 100

16 - 16 + b^2 = 100 - 16

b^2 = 84

Find \sqrt{84\\

5 0
3 years ago
Read 2 more answers
10 times the quantity 9 minus a number x
Svetllana [295]

Answer:

10 \times 9 - x \\ x = 10 \times 9 \\ x = 90

<h3><u>PLEASE</u><u> MARK</u><u> ME</u><u> BRAINLIEST</u><u>.</u></h3>
8 0
3 years ago
Read 2 more answers
If AC = x + 5 and AB = 3x - 1... what is the length of BC?
Hatshy [7]
If B is the midpoint of AC, then |AB| = |AC|.
|AB| = 3x + 2
|BC| = 5x - 10
Therefore we have the equation:
3x + 2 = 5x - 10     |subtract 2 from both sides
3x = 5x - 12      |subtract 5x from both sides
-2x = -12      |divide both sides by (-2)
x = 6

Read more on Brainly.com - brainly.com/question/11324096#readmore
4 0
3 years ago
Hi, can someone please help, and possibly explain the answer please.
mr_godi [17]

Answer:

x=\frac{-(-2)\±\sqrt{(-2)^2-4(3)(0)} }{2(3)}

Step-by-step explanation:

Quadratic formula: x=\frac{-b\±\sqrt{b^2-4ac} }{2a} when the equation is 0=ax^2+bx+c

The given equation is 1=-2x+3x^2+1. Let's first arrange this so its format looks like y=ax^2+bx+c:

1=-2x+3x^2+1

1=3x^2-2x+1

Subtract 1 from both sides of the equation

1-1=3x^2-2x+1-1\\0=3x^2-2x+0

Now, we can easily identify 3 as a, -2 as b and 0 as c. Plug these into the quadratic formula:

x=\frac{-b\±\sqrt{b^2-4ac} }{2a}\\x=\frac{-(-2)\±\sqrt{(-2)^2-4(3)(0)} }{2(3)}

I hope this helps!  

8 0
3 years ago
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