Answer:
0.6210
Step-by-step explanation:
Given that a Food Marketing Institute found that 39% of households spend more than $125 a week on groceries
Sample size n =87
Sample proportion will follow a normal distribution with p =0.39
and standard error = 
the probability that the sample proportion of households spending more than $125 a week is between 0.29 and 0.41
=
There is 0.6210 probability that the sample proportion of households spending more than $125 a week is between 0.29 and 0.41
Answer:
It's the first one.
Step-by-step explanation:

notice |7| 7 is positive, so we can simply remove the bars and use 7 by itself
Answer:
can't understand the question
Step-by-step explanation:
have a good day!