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Tema [17]
3 years ago
11

Can y’all please find the constant ratio for each

Mathematics
1 answer:
gogolik [260]3 years ago
7 0

Answer:

Step-by-step explanation:

1.

c.r.=10.5/10=105/100=21/20

or 10.5/10=1.05

2.

c.r=9/27=1/3

3.

c.r.=(3/4)/1=3/4

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What product is missing from the grid 4,6,9,14,49?
Inessa05 [86]

Answer:

12 is missing

Step-by-step explanation:

4 0
3 years ago
Find the volume of each ball. use the formula. where v is the volume and r is the radius. record the volume in table A of your s
pochemuha

Answer:

The volume of tennis ball = 38.808 cm^{3}.

                          Volume of golf ball = 33.523 cm^{3}.


Step-by-step explanation:

Given: The radius of the tennis ball is 2.1cm and the radius of thr golf ball is 2.0cm. the formula is V=4πr(to the 3rd power) /3 .

To find: Volume of tennis ball and golf ball .

Formula used: Volume = \frac{4 π r^{3} }{3} .

 pi(π) = \frac{22}{7} .

Explanation : We are given that

                     Radius of the tennis ball = 2.1 cm

                    radius  of the golf ball =2.0 cm.

We need to find the volume of each ball

So , plugging the given values of radius in above formula

Volume of the tennis =\frac{4*22(2.1)^{3} }{3*7}

On simplification we get, volume of tennis ball = 38.808 cm^{3}

Volume of the golf ball=\frac{4*22(2.0)^{3} }{3*7}

On simplification we get, volume of golf ball = 33.523 cm^{3}

Therefore , The volume of tennis ball = 38.808 cm^{3}.

                          Volume of golf ball = 33.523 cm^{3}.


7 0
3 years ago
Read 2 more answers
3 - 6k + 9g - 11 + 7g<br>(Distribute it with like terms and stuff)​
AURORKA [14]

Answer:

-6k+16g-8

Step-by-step explanation:

simplify

6 0
3 years ago
.....................ok​
Dafna11 [192]

Answer:

d. 2

Step-by-step explanation:

i hope this helps :)

5 0
3 years ago
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HELP ME PLEASE IVE BEEN STRUGGLING WITH THIS FOR SO LONG
Ber [7]

Answer:

<h2>m∠ACE = 90°</h2>

Step-by-step explanation:

Figure Interpretation:

m∠CBA + m∠CDE = 180

m∠BCA = (180-m∠CBA)/2

m∠DCE = (180-m∠CDE)/2

=======================

Then

m∠BCA + m∠DCE = (180-m∠CBA)/2 + (180-m∠CDE)/2

                                = [360-(m∠CBA+m∠CDE)]/2

                                = [360 - 180]/2

                                = 90

finally,

m∠ACE= 180 - (m∠BCA + m∠DCE)

             = 180 - 90

             = 90

8 0
2 years ago
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