<h3>x²+5x+3+2x²+10x15 =0</h3><h3>x²+2x²+5x+10x+3+15=0</h3><h3>3x²+15x+18=0</h3><h3>3(x²+5x+6) =0 because 3 is common factor</h3><h3>3(x²+3x+2x+6) spill the middle term</h3><h3>3(x(x+3)+2(x+3) take the common factor from term</h3><h3>3(x+2) (x+3)</h3>
<h3>answer is 3(x+2) (x+3)</h3>
please mark this answer as brainlist
Variable
i did not know bout dis edit ting
Answer:
Required output = 14
Step-by-step explanation:
Sum of the input 3 and 4 = 3 + 4
Twice the sum means two times.
So, to find twice the sum of the input 3 and 4, we need to multiply the sum by 2.
2(3 + 4)
Perform the addition inside the parentheses.
2(3 + 4) = 2(7)
Now, multiply.
2(3 + 4) = 14
Hence, required output = 14
ANSWER IS C because I looked it up
Answer:
B
Step-by-step explanation:
