Answer:
1) 5 * 18
Step-by-step explanation:
Because 6*3 = 18
5*6*3 = 5*18
<u>Answer:</u>
The probability of getting two good coils when two coils are randomly selected if the first selection is replaced before the second is made is 0.7744
<u>Solution:</u>
Total number of coils = number of good coils + defective coils = 88 + 12 = 100
p(getting two good coils for two selection) = p( getting 2 good coils for first selection )
p(getting 2 good coils for second selection)
p(first selection) = p(second selection) = 
Hence, p(getting 2 good coil for two selection) = 
(c+8)(c-8)
3(2y+5)(2y-5)
There are no like terms so it's still ab^2-b