Question

Please help me with this as well

Answer 1

Answer:

$y = \dfrac{3 + 6\sqrt{2}}{4} ~~~\textrm{and}~~~y = \dfrac{3 - 6\sqrt{2}}{4}$

Step-by-step explanation:

$(4y - 3)^2 = 72$

$4y - 3 = \pm\sqrt{72}$

$4y - 3 = \pm 6\sqrt{2}$

$4y = 3 \pm 6\sqrt{2}$

$y = \dfrac{3 + 6\sqrt{2}}{4}~~~\textrm{or}~~~y = \dfrac{3 - 6\sqrt{2}}{4}$