Answer:
2 (real) solutions.
Step-by-step explanation:
A quadratic always has two solutions, whether they are real or complex.
Sometimes the solution is complex, involving complex numbers (2 complex), sometimes they are real and distinct (2 real), and sometimes they are real and coincident (still two real, but they are the same).
In the case of
x^2+3x = 3, or
x² + 3x -3 = 0
we apply the quadratic formula to get
x = (-3 +/- sqrt(3^2+4(1)(3))/2
to give the two solutions
{(sqrt(21)-3)/2, -(sqrt(21)+3)/2,}
both of which are real.
Answer:
y = -2x - 1
Step-by-step explanation:
Rewrite y + 7 = -2(x - 3) in slope-intercept form (which is y = mx + b):
First, perform the indicated multiplication:
y + 7 = -2x + 6
Combining the constants, we get
y = -2x - 1
This is the desired equation in slope-intercept form. slope is -2 and y-intercept is -1.
Answer:
C.) x= -4
Step-by-step explanation:
just took the test on edg. 2020
Hello,
f(π/2)=4*sin(π/2)-2=4*1-2=2
f(0)=4*sin(0)-2=0-2=-2
rate=(2+2)/(π/2-0)=8/π
Answer D
