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RoseWind [281]
3 years ago
8

A random number generator is selecting numbers in the range 1 through 50. What is the probability that the random number generat

or will select a number that is not multiple of 7
Mathematics
2 answers:
kati45 [8]3 years ago
7 0

Answer:

7,14,21,28,35,42,49 are all dividible by 7. That are 7 Numbers. However we are looking for All the Numbers that are not a multiple of 7.

So 50-7=43.

There are 43 Numbers which are not a multiple of 7.

So 43/50=0.86

The probability is 0.86 or a 86% chance that the generator will select a Number which is not a multiple of 7.

N76 [4]3 years ago
3 0

Answer:

43/50

Step-by-step explanation:

Use the complement rule to find this probability. The complement of this event is the event that the random number generator selects a number that is a multiple of 7. There are 7 multiples of 7 that the generator could possibly select, namely 7,14,21,28,35,42,49, so the probability that the generator will select a multiple of 7 is 750. The probability of the complement is 1−750=4350.

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A nature center offers 2 guided walks. The morning walk is two-third mile. The evening walk is three-sixths mile. Which walk is
MArishka [77]

Answer:

Evening walk is shorter.  

Step-by-step explanation:

We have been given that a nature center offers 2 guided walks. The morning walk is two-third mile. The evening walk is three-sixths mile. We are asked to find the shorter walk.

Let us compare both fractions by making the same denominator.

\text{Two-thirds}=\frac{2}{3}

\text{Two-thirds}=\frac{2\times2}{3\times2}

\text{Two-thirds}=\frac{4}{6}

\text{Three-sixth}=\frac{3}{6}

Upon making common denominator, we can see that two-thirds are equal to four sixths.

Since three-sixths is less than four-sixths, therefore, evening walk is shorter.

We will draw two rectangles, one with 6 sub-parts and other with three sub-parts.

We will shade 2 parts out of 3 sub-parts to represent 2/3 and shade 3 parts out of 6 sub-parts to represent 3/6.

Then we will further divide three sub-parts into 6 sub-parts as shown in the diagram that will represent 4/6.

5 0
3 years ago
A television with a 5:3 screen shows an image with a ratio of 5:4 which creates a letter boxed image. What percent of the screen
lions [1.4K]

Answer:

C

Step-by-step explanation:

8 0
3 years ago
Please help! Brainliest. No bots will be acceptable.
Vitek1552 [10]

Answer:

7.5 cups of raisins, 10 cups of peanuts and 5 cups of chocolate chips.

Step-by-step explanation:

We are given that,

The amount of ingredients needed for the trail mix are,

Raisins =  cup

Peanuts = 1 cup

Chocolate chips =  cup

Since, Kiran needs to make 10 cups of the trail mix.

The amount of ingredients needed will be,

Raisins =  =  = 7.5 cups

Peanuts = 1 × 10 = 10 cups

Chocolate chips =  = 5 cups

Hence, the ingredients needed are 7.5 cups of raisins, 10 cups of peanuts and 5 cups of chocolate chips.

5 0
3 years ago
Read 2 more answers
This question is from trignometry of class 9.​
Ne4ueva [31]

Answer:

  4.2π cm ≈ 13.19 cm

Step-by-step explanation:

The length s of an arc of a circle with radius r and central angle θ (in radians) is ...

  s = rθ

Here, we have ...

  s = (5.6 cm)(3π/4) = 4.2π cm ≈ 13.19 cm

8 0
3 years ago
A Packaging Company produces boxes out of cardboard and has a specified weight of 16 oz. A random sample of 36 boxes yielded a s
user100 [1]

Answer:

The margin of error is of 0.73 oz.

The 99% confidence interval for the true mean weight of the boxes is between 14.57 oz and 16.03 oz. This means that we are 99% sure that the true mean weight of all boxed produced by the Packaging Company is between these two values, and that the specified weight is in this interval.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.005 = 0.995, so Z = 2.575.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 2.575\frac{1.7}{\sqrt{36}} = 0.73

The margin of error is of 0.73 oz.

The lower end of the interval is the sample mean subtracted by M. So it is 15.3 - 0.73 = 14.57 oz.

The upper end of the interval is the sample mean added to M. So it is 15.3 + 0.73 = 16.03 oz.

The 99% confidence interval for the true mean weight of the boxes is between 14.57 oz and 16.03 oz. This means that we are 99% sure that the true mean weight of all boxed produced by the Packaging Company is between these two values, and that the specified weight is in this interval.

4 0
3 years ago
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