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3 years ago

What construction does the image below demonstrate?

Mathematics

2 answers:

gladu [14]3 years ago

8 0

<h2>Answer:</h2>

The construction that the image demonstrate below is:

Hexagon

<h2>Step-by-step explanation:</h2>

From the figure we see that the figures denotes the construction of a polygon named hexagon.

The steps fro construction are as follows:

Draw a circle.

Take a compass and put the point of compass at any point on the circumference and draw a circle by taking that point at center, let it be B.

Next keep the point of compass at the point where the arc in step 2 meets the circle let it be C and continue to do so till we reach B.

Now join the points BCDEFGB to obtain a hexagon.

Anna [14]3 years ago

4 0

The image shows the construction of an inscribed hexagon using technology.

Hope this helps:)

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3 years ago

In which number does the digit 7 have a value that is 10 times as great as the digit 7 in the number 0.9750

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3 years ago

The length of a rectangle is 6 more than twice the width. if the area is 40 cm^2, find the length and breadth of the rectangle

ra1l [238]

Answer: 3.217 & 12.434

Step-by-step explanation:

If we use <em>w</em> to represent the width, the length will be 6 more than 2 times w.

Hence, the length is $2w+6$ .

The area of a rectangle would be its length times its width, so let's make an equation to represent it's area.

$A=w(2w+6)$

We can also substitute 40 in for A as it's given in the question.

$40 = w(2w+6)$

Distributing <em>w</em> by multiplying it by both terms in the parentheses, we get

$40 = 2w^2+6w$

We can make the equation simpler by dividing both sides by 2.

$20 = w^2+3w$

Subtracting both sides by 20 will make the left-hand side 0.

$0=w^2+3w-20$

Now that we have put this <em>quadratic equation</em> into standard form (ax²+bx+c), we can find its solutions using the quadratic formula.

For reference, the quadratic formula is

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

In this case, a is 1, b is 3, and c is -20.

Substituting, we get

$w=\frac{-3\pm\sqrt{3^2-4(1)(-20)}}{2(1)}$

$w= \frac{-3\pm\sqrt{9+80}}{2}$

$w=\frac{-3+\sqrt{89}}{2}\hspace{0.1cm}or\hspace{0.1cm}\frac{-3-\sqrt{89}}{2}$

Since the second solution results in a negative number, it cannot be the length of w.

$w=\frac{-3+\sqrt{89}}{2}\approx3.217$

The width/breadth of the rectangle is 3.217 cm.

To calculate the length, let's substitute the width into the expression for the length:

$l=2(3.217)+6$

$l=12.434$

The length of this rectangle is 12.434 cm.

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2 years ago

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3 years ago

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