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3 years ago

Negative 4 4/25 as a decimal

Mathematics

1 answer:

loris [4]3 years ago

3 0

The answer is of -4 4/25 is -4.16

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The price of a video game was reduced from $60 to $45. by what percentage was the price of the video game reduced

storchak [24]

Answer:

It was reduce by 25%

Step-by-step explanation:

45 so it would be reduced by 25%

___

x 100% = 75%

3 0

3 years ago

Read 2 more answers

Ben is 12 years older than Ishaan. Ben and Ishaan first met two years ago. Three years ago, Ben was 4 times as old as Ishaan. Ho

Len [333]

Answer:

I think that Ishaan is 6

Step-by-step explanation:

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4 0

3 years ago

Part A: Factor 2x2y2 + 6xy2 + 18x2y2. Show your work.

prohojiy [21]

Answer:

$2xy^2(10x+3)$

$(x+5)^2$

$(x-6)(x+6)$

Step-by-step explanation:

Part A. The expression $2x^2y^2+6xy^2+18x^2y^2$ consists of three terms: $2x^2y^2,\ \ 6xy^2,\ \ 18x^2y^2$ The first and the last terms are like terms, we can add them:

$2x^2y^2+18x^2y^2=20x^2y^2$

Now,

$20x^2y^2=2xy^2\cdot 10x\\ \\6xy^2=2xy^2\cdot 3$

So,

$2x^2y^2+6xy^2+18x^2y^2=2xy^2(10x+3)$

Part B. The expression $x^2+10x+25$ is a square of $x+5,$ so

$x^2+10x+25=(x+5)^2$

Part C. Use the difference of squares formula:

$x^2-36=x^2-6^2=(x-6)(x+6)$

5 0

3 years ago

Please help fast!!!<br><br> A circle has a circumference of 10pi yards find the area in terms of pi

klemol [59]

25pi yards squared is the area

3 0

3 years ago

Please help!!! (Ignore the AD it’s actually supposed to be DC)

pashok25 [27]

Answer:

BD = 22, DC = 11√3

Step-by-step explanation:

In triangle ABC, ∠B = 45°, ∠C = 90°. Hence:

∠A + ∠B + ∠C = 180° (sum of angles in a triangle)

∠A + 45 + 90 = 180

∠A + 135 = 180

∠A = 45°

Using sine rule to find BC:

$\frac{BC}{sinA}=\frac{AB}{sinC} \\\\\frac{BC}{sin45}=\frac{11\sqrt{2} }{sin90} \\\\BC=\frac{11\sqrt{2}*sin45 }{sin90} \\BC=11$

In triangle BCD, ∠D = 30°, ∠C = 90°. Hence:

∠D + ∠B + ∠C = 180° (sum of angles in a triangle)

∠B + 30 + 90 = 180

∠B + 120 = 180

∠B = 60°

Using sine rule to find BD:

$\frac{BD}{sinC}=\frac{BC}{sinD} \\\\\frac{BD}{sin90} =\frac{11}{sin30} \\\\BD=\frac{11*sin90}{sin30}\\\\BD=22$

Using sin rule to find DC:

$\frac{DC}{sinB}=\frac{BC}{sinD} \\\\\frac{DC}{sin60} =\frac{11}{sin30} \\\\DC=\frac{11*sin60}{sin30}\\\\DC=11\sqrt{3}$

6 0

3 years ago