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Burka [1]
2 years ago
5

Please Help!!!!!!!!!!!

Mathematics
1 answer:
Nezavi [6.7K]2 years ago
5 0

Answer:

C= 30

Step-by-step explanation:

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Step-by-step explanation:

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Bas_tet [7]

Answer:

  no solution

Step-by-step explanation:

If we subtract the left side of the equation, we get ...

  \dfrac{m^2+9}{m^2-9}-\dfrac{3}{m+3}+\dfrac{3}{3-m}=0\\\\\dfrac{m^2+9-3(m-3)-3(m+3)}{(m-3)(m+3)}=0\\\\\dfrac{m^2-6m+9}{(m-3)(m+3)}=0=\dfrac{(m-3)^2}{(m-3)(m+3)}\\\\\dfrac{m-3}{m+3}=0\quad\text{m$\ne$3}

This equation will equal zero only if m=3, which is disallowed because it makes the denominator zero. Thus, there is no solution.

7 0
3 years ago
Helpp plss this needs to be done before 11:59 I’ll do anything for you just helpp
Alexus [3.1K]

Answer:

20=91.35*2

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Hope This Helps!!!

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aleksandrvk [35]

It wouldn't let me post, so I screenshotted:

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2 years ago
I need help please i did not understand
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Answer:

Step-by-step explanation:

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