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Whitepunk [10]
3 years ago
10

The account balance on April 1st is $60.15. On April 15th a payment of $51.00 is made. On April 25th a purchase of $91.27 is mad

e. What is the finance charge if the annual rate is 18%? What is the new account balance? (Use the unpaid balance method.) Finance charge = New account balance =
Mathematics
2 answers:
user100 [1]3 years ago
7 0

Answer:

Finance charge = $0.13725

New balance =$100.55

Step-by-step explanation:

Given : The account balance on April 1st is $60.15. On April 15th a payment of $51.00 is made. On April 25th a purchase of $91.27 is made. The annual rate is 18%.

To find : What is the finance charge and what is his new account balance?  

Solution :

Previous balance = $60.15

Payment = $51

We find the unpaid balance,

Unpaid balance = Previous balance - Payments

                           = $60.15 - $51

Unpaid balance  = $9.15

We have given rate of interest= 18%=0.18

Now, we find the finance charge

Finance charge = Finance rate × Unpaid balance

Finance charge = \frac{0.18}{12} \times 9.15

Finance charge = $0.13725

New balance =  Unpaid balance + finance charge + new transaction

New balance =  $9.15 +$0.13725+ $91.27

New balance =$100.55

natta225 [31]3 years ago
5 0
Hi there:-)

Unpaid balance=60.15−51=9.15
Finance charge=9.15×(0.18÷12)=0.14
New balance=9.15+0.14+91.27=100.56

Hope it helps
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professor190 [17]

Answer:

Given that,

The number of grams A of a certain radioactive substance present at time, in years

from the present, t is given by the formula

A=45e^{-0.0045(t)}

a) To find the initial amount of this substance

At t=0, we get

A=45e^{-0.0045(0)}A=45e^0

We know that e^0=1 ( anything to the power zero is 1)

we get,

A=45

The initial amount of the substance is 45 grams

b)To find thehalf-life of this substance

To find t when the substance becames half the amount.

A=45/2

Substitute this we get,

\frac{45}{2}=45e^{-0.0045(t)}

\frac{1}{2}=e^{-0.0045(t)}

Taking natural logarithm on both sides we get,

\ln (\frac{1}{2})=-0.0045(t)^{}(-1)\ln (\frac{1}{2})=0.0045(t)\ln (\frac{1}{2})^{-1}=0.0045(t)\ln (2)=0.0045(t)0.6931=0.0045(t)t=\frac{0.6931}{0.0045}t=154.02

Half-life of this substance is 154.02

c) To find the amount of substance will be present around in 2500 years

Put t=2500

we get,

A=45e^{-0.0045(2500)}A=45e^{-11.25}A=45\times0.000013=0.000585A=0.000585

The amount of substance will be present around in 2500 years is 0.000585 grams

4 0
1 year ago
Combine 5b/4a+b/3a-3b/a
lawyer [7]
I believe 3b/6a which could reduce to b/3a.
7 0
3 years ago
Two bags with 3 oranges in each bag is the same amount as 3 bags with 2 oranges in each bag. Which property of multiplication do
kodGreya [7K]

Answer:

Commutative Property

Step-by-step explanation:

The property of multiplication that is being demonstrated is known as Commutative Property. This property basically shows that when multiplying two numbers the actual order in which they are multiplied does not matter and does not affect the result at all. For example, the in this scenario to get the total number of oranges we have to multiply the number of bags by the number of oranges in each bag, but whatever way we do this they equal the same

2 bags * 3 oranges per bag = 6 oranges

3 bags * 2 oranges per bag = 6 oranges

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7 0
3 years ago
Un paracaidista que pesa 70 N es lanzado de un avión. halla su masa​
77julia77 [94]

Answer:

<em>La masa del paracaidista es 7.14 Kg</em>

Step-by-step explanation:

<u>Peso y Masa</u>

La masa de un objeto es una medida de la cantidad de material que el objeto posee. Sus unidades más comunes son el Kg, gr, lb, Ton.

El peso de un objeto de masa m es la fuerza con la cual la Tierra atrae al objeto a través de la aceleración de gravedad g. Sus unidades son iguales a las de cualquier fuerza, es decir, Nw, Kgf, Dina. Su fórmula es:

P=m.g

Si tenemos el peso P=70 N, podemos calcular la masa, despejándola de la fórmula:

\displaystyle m=\frac{P}{g}

Sustituyendo los valores:

\displaystyle m=\frac{70}{9.8}=7.14\ Kg

La masa del paracaidista es 7.14 Kg

8 0
3 years ago
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den301095 [7]
B

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