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kondaur [170]
3 years ago
10

Many were _____________ by the warm actor's wit and charm.

SAT
1 answer:
docker41 [41]3 years ago
3 0
D, sounds like your answer
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Make an inference about the characters and their motivations in this scene. What did juliet do? what did the nurse do? what moti
Marat540 [252]

People often play a lot of roles. The answers to the questions are below.

  • Juliet  was said to have sent the nurse to speak with Romeo.
  • The nurse agreed to this request.
  • What motivated Juliet to make this request is that her desire to marry Romeo.
  • What motivated the nurse to go on this quest is that She cares about Juliet's happiness.

<h3>What is the Romeo and Juliet story about?</h3>

The story of Juliet and Romeo is one that is said to  be based on the life story of two real lovers who were said to have lived and died for each other. The place where this people  stayed was in Verona, Italy in the year 1303.

Shakespeare is said to be the one  who discovered this tragic love story in the poem of Arthur Brooke in 1562 which was titled “The Tragical History of Romeo and Juliet”.

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7 0
2 years ago
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The "sunflower-bordered roads" instill in the narrator a sense of A) adventure. B) creativity. Eliminate C) freedom. D) regret.
Degger [83]

the answer would be B


5 0
3 years ago
Read 2 more answers
In which compound is the percent composition by mass of chlorine (cl) equal to 42%?.
anygoal [31]

There are different kinds of compositions. The percentage mass composition of chlorine is 42% in HClO3 (gram-formula mass = 84 g/mol)

<h3>What is HClO3 known as?</h3>

This HClO3  is known to be popularly called as Chloric acid.

Percentage mass of chlorine is formula:

Percentage mass composition = mass of element * 100%/mass of compound.

Therefore;

HClO3 (gram-formula mass = 84 g/mol)

Percentage mass composition of chlorine = 35 * 100% / 84 = 42%

See full question below.

In which compound is the percent composition by mass of chlorine equal to 42%?

(1) HClO (gram-formula mass = 52 g/mol)

(2) HClO2 (gram-formula mass = 68 g/mol)

(3) HClO3 (gram-formula mass = 84 g/mol)

(4) HClO4 (gram-formula mass = 100. g/mol)

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7 0
2 years ago
A point charge q1 = -4. 00 nc is at the point x = 0. 60 m, y = 0. 80 m , and a second point charge q2 = +6. 00 nc is at the poin
Alekssandra [29.7K]

The net electric field is the vector sum of the components of the electric

field produced by the two charges.

The values of the magnitude and direction of the net electric field at the origin (approximate values) are;

  • 131.6 N/C
  • 12.6 ° above the negative x–axis

<h3>How are the net electric field magnitude and direction calculated?</h3>

The possible questions based on a similar question posted online are;

(a) The net electric field at the origin.

The electric field due to charge q₁ is given as follows;

\vec E_{1x} = \mathbf{ \dfrac{1}{4 \cdot \pi \cdot \epsilon_0} \cdot \dfrac{q_1}{\vec{r}^2_2}}

Which gives;

\vec{E}_{1x} =\mathbf{ \dfrac{\left(9 \times 10^9 \, N \cdot m/C^2 \right) \cdot \left(-4 \, nC \times \dfrac{10^{-9}C}{1 \, nC} \right)}{\left(1 \, m \right)^2}} \cdot cos\left(arctan\left(\dfrac{0.8}{0.6} \right) \right) =-21.6 \, N/C

\vec{E}_{1y} = \mathbf{\dfrac{\left(9 \times 10^9 \, N \cdot m/C^2 \right) \cdot \left(-4 \, nC \times \dfrac{10^{-9}C}{1 \, nC} \right)}{\left(1 \, m \right)^2}} \cdot sin\left(arctan\left(\dfrac{0.8}{0.6} \right) \right) = 28.8 \, N/C

Which gives;

\vec{E}_1 = \mathbf{21.6 \, N/C  \cdot \hat x +  28.8 \, N/C \hat y}

\vec{E}_{2x} = \dfrac{\left(9 \times 10^9 \, N \cdot m/C^2 \right) \cdot \left(6.00 \, nC \times \dfrac{10^{-9}C}{1 \, nC} \right)}{\left(1 \, m \right)^2} = 150 \, N/C

Therefore;

\vec  {E} = \left[ 21.6 \, N/C - 150 \, N/C \right] \left( \hat x \right) + \left(28.8 \, N/C \right) \left( \hat y \right)

\vec  {E} = \mathbf{\left( -128.4 \, N/C  \right) \left( \hat x \right) + \left(28.8 \, N/C \right) \left( \hat y \right)}

The magnitude of the net electric field is therefore;

E = \sqrt{(-128.4^2 + 28.8^2)} ≈ 131.6

  • The magnitude of the net electric field at the origin is E ≈<u> 131.6 N/C</u>

(b) The direction of the net electric field at the origin.

  • The \ direction \ is \ arctan \left(\dfrac{28.8}{-128.4} \right) \approx \underline{ 12.6^{\circ}} \ above \ the \ negative \ x-axis

Learn more about electric field strength here:

brainly.com/question/14743939

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3 0
2 years ago
I want to know how to solve it.
Novay_Z [31]

Answer:

f(1+g(1))=2 is your answer

Explanation:

we have

f(x)={2x-2}/(x²+1)

g(x)=x²+1

now

f(1+g(1))=f(1+(1²+1))=f(1+2)=f(3)={2×3-2}/(1²+1)=4/2=2

8 0
3 years ago
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