3 years ago

If A = (0,0) and B = (8, 2), what is the length of AB?

Mathematics

1 answer:

alexira [117]3 years ago

6 0

the legenth is (8,2) .

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See below for the proof of the equation $\frac{ax + by}{x + y} - \frac{ax - by}{x - y}= 2(a - b)$

<h3>How to prove the equation?</h3>

The equation is given as:

$\frac{ax + by}{x + y} - \frac{ax - by}{x - y}= 2(a - b)$

Take the LCM

$\frac{(ax + by)(x - y) -(ax - by)(x + y)}{(x + y)(x - y)}= 2(a - b)$

Expand

$\frac{ax^2 - axy + bxy - by^2 -ax^2 - axy + bxy + by^2}{(x + y)(x - y)}= 2(a - b)$

Evaluate the like terms

$\frac{-2axy + 2bxy }{(x + y)(x - y)}= 2(a - b)$

Rewrite as:

$\frac{-2axy + 2bxy }{x^2 - y^2}= 2(a - b)$

Factorize the numerator

$\frac{2(a - b)(x^2 - y^2)}{x^2 - y^2}= 2(a - b)$

Divide

2(a - b)= 2(a - b)

Both sides are equal

Hence, the equation $\frac{ax + by}{x + y} - \frac{ax - by}{x - y}= 2(a - b)$ has been proved