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Nataly_w [17]
3 years ago
7

Mary had a 3-inch piece of ribbon. She cut it in half. How long were the new pieces?

Mathematics
1 answer:
Andreyy893 years ago
6 0
3 divided by 2 is 1.5
each piece is 1.5 
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What’s the distance between points (5,6) and (9,9)
iragen [17]

Answer:

(4,3)

the distance between x1 and x2 then y1 then y2

6 0
3 years ago
OH NO!!! Madeleine’s data has been corrupted, again! Using the incomplete data file below, which she was able to recover from he
-Dominant- [34]

Answer:

a. N=25

b. X[bar]= 60.52

c. Y[bar]= 106.72

d. SSx= 115.24

e. ∑X*∑Y = 4036684

f. SSxy= 202020.3296

g. √(SSx*SSy)= 449.46

Step-by-step explanation:

Hello!

Using the attached data you need to calculate some statistics.

a) N

The sample size is listed under the first column "subject" You can see that 25 subjects qhere studied so N=25.

b.

The mean of set X is equal to X[bar]= ∑X/n= 1513/25= 60.52

∑X is listed in the second table.

c.

The mean of ser Y is Y[bar]= ∑Y/n= 2668/25= 106.72

∑Y is listed in the second table.

d.

Sum of Squares of set X SSx= ∑X²-[(∑X)²/n]= 91682-[(1513)²/25]= 115.24

e.

∑X*∑Y =1513*2668= 4036684

f.

SSxy= (∑X²-[(∑X)²/n]) * (∑Y²-[(∑Y)²/n])= (91682-[(1513)²/25]) * (286482*[(2668)²/25])= 202020.3296

g.

√(SSx*SSy)= √(115.24*1753)= 449.46

I hope you have a SUPER day!

3 0
3 years ago
Help me with math please, quickly
irga5000 [103]

Answer:

3\neq -3

False

Step-by-step explanation:

y=3x-9\\\\x-\frac{1}{3}y=-3

You substitute y for the second equation.

x-\frac{1}{3} y=-3\\\\x-\frac{1}{3}(3x-9)=-3

Then you have to distribute -\frac{1}{3} .

x-x+3=-3

Combine like terms.

3\neq -3

7 0
3 years ago
Read 2 more answers
What is the absolute value of 4+7i is equal to the square root of ______
nexus9112 [7]
The answer too your question is 65 it is equal to the square root of 65
4 0
3 years ago
Read 2 more answers
Use the data in LAWSCH85 for this exercise. (i) Using the same model as in Problem 4 in Chapter 3, state and test the null hypot
natka813 [3]

Answer:

Step-by-step explanation:

In the model

Log (salary) = B0 + B1LSAT +B2GPA +B3log(libvol) +B4log(cost)+B5 rank+u

The hypothesis that rank has no effect on log (salary) is H0:B5 = 0. The estimated equation (now with standard errors) is

               Log (salary) =    8.34 +    .0047 LSAT +   .248 GPA +   .095 log(libvol)

                                        (0.53)     (.0040)              (.090)            (.033)

                                         +     .038 log(cost)    – .0033 rank

                                              (.032)                    (.0003)

                   n = 136,    R2 = .842.

The t statistic on rank is –11(i.e. 0.0033/0.0003), which is very significant. If rank decreases by 10 (which is a move up for a law school), median starting salary is predicted to increase by about 3.3%.

(ii) LSAT is not statistically significant (t statistic ≈1.18) but GPA is very significance (t statistic  ≈2.76). The test for joint significance is moot given that GPA is so significant, but for completeness the F statistic is about 9.95 (with 2 and 130 df) and p-value ≈.0001.

6 0
3 years ago
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