Answer:
48+23(6)½
Step-by-step explanation:
A = l × w
A =[(8-(6)^½) × (9+4(6)^½)]
A =8(9+4(6)^½) + [-(6)^½(9+4(6)^½]
A =(72 + 32(6)^½ - 9(6)^½ - 24)
A =(72 - 24 + 32(6)^½ - 9(6)^½)
A =(48 + 23(6)^½)
You still want at most
(15x) + (22y) ≤ 100(-z) (equation used)
0 ≤ z ≤ 10 (amount you want to leave unspent)
y ≥ 1 (amount of dress shirt you need)
This is your system of equation, in which the numbers must fulfill both equations
hope this helps
Answer:
I would expect 6 of the next 12 flights to be late
Answer:
A
Step-by-step explanation:
This is the same as ((2^3)/(4^2))*((2^3)/(4^2))*((2^3)/(4^2))*((2^3)/(4^2))*((2^3)/(4^2)) which is equal to (2^(3+3+3+3+3)/4^(2+2+2+2+2)), so its (2^15/4^10)
Given: 12x +20
factor out a two: 2(6x +10)
factor out a four: 4(3x+5)
factor out 3/4: 3/4(9x +15)
factor out 1/2: 1/2(6x +10)
Hint: think of Multiples of 12 and 20
Hope this helps!
