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zhannawk [14.2K]
3 years ago
11

PLS HELPPP!!!!!! just to be clear c is not correct ​

Mathematics
1 answer:
mojhsa [17]3 years ago
8 0

Answer: im gonna guess b?

Step-by-step explanation:

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The product of the roots of the equation x2 + x=2 is:<br> 0-2<br> 01
gregori [183]

Answer:

-2

Step-by-step explanation:

x^2 + x=2

Subtract 2 from each side

x^2 + x-2=2-2

x^2 + x-2=0

Factor

What 2 numbers multiply to -2 and add to 1

2*-1 = -2

2+-1 =1

(x-1)(x+2)=0

Using the zero product property

x-1 = 0  x+2 = 0

x=1        x = -2

Product of the roots

1*-2 = -2

5 0
3 years ago
What are the answers to these thank you and please tell me how to get it
mote1985 [20]
5-3(1/2x+2)=-7
-3(1/2x+2)=-7-5
(1/2x+2)=4
1/2x=2
x=4
just to give u an idea
4 0
3 years ago
The diameter of a sphere is 4 centimeters.
ELEN [110]
The volume of a sphere refers to the number of cubic units that will exactly fill a sphere. The volume of a sphere can be found or calculate by using the formula V=4/3πr^3, where r represents the radius of the figure.

In this exercise is given that a sphere has a radius of 4 centimeters and it is asked to find its volume and use 3.14 as the value of π or pi. The first step would be substitute the values into the previous mention formula.

V=4/3πr^3
V=4/3(3.14)(4 cm)^3
V=4/3)(3.14)(64 cm^3)
V=267.9 cm^3
The volume of the sphere is 267.9 cubic centimeters.

7 0
3 years ago
Read 2 more answers
Find the general solution of the following ODE: y' + 1/t y = 3 cos(2t), t &gt; 0.
Margarita [4]

Answer:

y = 3sin2t/2 - 3cos2t/4t + C/t

Step-by-step explanation:

The differential equation y' + 1/t y = 3 cos(2t) is a first order differential equation in the form y'+p(t)y = q(t) with integrating factor I = e^∫p(t)dt

Comparing the standard form with the given differential equation.

p(t) = 1/t and q(t) = 3cos(2t)

I = e^∫1/tdt

I = e^ln(t)

I = t

The general solution for first a first order DE is expressed as;

y×I = ∫q(t)Idt + C where I is the integrating factor and C is the constant of integration.

yt = ∫t(3cos2t)dt

yt = 3∫t(cos2t)dt ...... 1

Integrating ∫t(cos2t)dt using integration by part.

Let u = t, dv = cos2tdt

du/dt = 1; du = dt

v = ∫(cos2t)dt

v = sin2t/2

∫t(cos2t)dt = t(sin2t/2) + ∫(sin2t)/2dt

= tsin2t/2 - cos2t/4 ..... 2

Substituting equation 2 into 1

yt = 3(tsin2t/2 - cos2t/4) + C

Divide through by t

y = 3sin2t/2 - 3cos2t/4t + C/t

Hence the general solution to the ODE is y = 3sin2t/2 - 3cos2t/4t + C/t

3 0
3 years ago
Twice a number decreased by 16 is 64.
Artyom0805 [142]
You number is 40 40 x 2= 80- 16 =64 your welcome :)
8 0
3 years ago
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