8^2 is 64 and 2^2 is 4. When you add them together you get 68.
(8+2)^2 is the same as 10^2 which is 100.
68≠100
A: Perimeter = 2*length + 2*width = 2x^2 + 14x + 4
B: Area = length*width = 4x^3 + 12x^2 + 8x
One possible probability is 1/10.
Since P(b) = 1/5, we know that there must be some multiple of 5 as the total number of markers.
There cannot be 5 markers in the box; if there is only 1 blue out of 5 markers, it is impossible for there to be any red markers and have a probability less than 1/5.
Using a total of 10 markers, there would be 2/10 blue to have a probability of 1/5. This means there would be 1/10 red. We know nothing about the number of green markers, so there can be as many as we want, in theory. This means the other 7 markers could be green.
Answer:
acute and isosceles
Step-by-step explanation:
acute because all angles less than 90
isosceles because 2 sides are equal length
<em>a</em> = 8 - a train arrives at the station once every 8 minutes, so for any given 8 minute interval, a randomly selected train has uniform probability of arriving at the station at some point in this time.
<em>f(x)</em> = 1/8 - the area under the graph of <em>f(x)</em> must be equal to 1. This area corresponds to a rectangle with length <em>a</em> = 8 and height <em>x</em> such that 8<em>x</em> = 1. Solving for <em>x</em> gives 1/8.
<em>P</em> = 5/8 - this is equal to the area under the graph over the interval [0, 5], which is the area of a rectangle with length 5 and height 1/8.
