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Mkey [24]
3 years ago
9

8 to the power of negative 2 × a to the power of 7

Mathematics
1 answer:
solniwko [45]3 years ago
5 0
I'm sorry, all you did was say something. We need a question if you want an answer.
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Find a third point on the line that passes through (4, 1) and (0, 3)
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3 years ago
A triangular lot has sides of 215m, 185m, and 125m. Find the measures of the angles at its corners
Vlada [557]

Answer:

The measures of the angles at its corners are 59.1\°,35.4\°,85.5\°

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the measure of angle A

Applying the law of cosines

185^{2}= 215^{2}+125^{2}-2(215)(125)cos(A)

2(215)(125)cos(A)= 215^{2}+125^{2}-185^{2}

cos(A)= [215^{2}+125^{2}-185^{2}]/(2(215)(125))cos(A)=0.513953

A=arccos(0.513953)=59.1\°

step 2

Find the measure of angle B

Applying the law of cosines

125^{2}= 215^{2}+185^{2}-2(215)(185)cos(B)

2(215)(185)cos(B)= 215^{2}+185^{2}-125^{2}

cos(B)= [215^{2}+185^{2}-125^{2}]/(2(215)(185))cos(B)=0.81489

B=arccos(0.81489)=35.4\°

step 3

Find the measure of angle C

Applying the law of cosines

215^{2}= 125^{2}+185^{2}-2(125)(185)cos(C)

2(125)(185)cos(C)= 125^{2}+185^{2}-215^{2}

cos(C)= [125^{2}+185^{2}-215^{2}]/(2(125)(185))cos(C)=0.0784

C=arccos(0.0784)=85.5\°

3 0
3 years ago
Use the Distributive Property to write each expression in expanded form.
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A. 3x+21

B. 25-5x

C.8x-16

D.x^2+6x+24

7 0
3 years ago
Read 2 more answers
I need help on number 10 urgently.
grigory [225]

Answer: Option A. 288 cubic inches

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3 years ago
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A, b, c and d are positive integers, such that a+b+ ab = 76, c+d+ cd = 54. Find (a+b+c+d)·a·b·c·d.
lutik1710 [3]

Notice that

(1 + <em>x</em>)(1 + <em>y</em>) = 1 + <em>x</em> + <em>y</em> + <em>x y</em>

So we can add 1 to both sides of both equations, and we use the property above to get

<em>a</em> + <em>b</em> + <em>a b</em> = 76  ==>  (1 + <em>a</em>)(1 + <em>b</em>) = 77

and

<em>c</em> + <em>d</em> + <em>c d</em> = 54  ==>  (1 + <em>c</em>)(1 + <em>d</em>) = 55

Now, 77 = 7*11 and 55 = 5*11, so we get

<em>a</em> + 1 = 7  ==>  <em>a</em> = 6

<em>b</em> + 1 = 11  ==>  <em>b</em> = 10

(or the other way around, since the given relations are symmetric)

and

<em>c</em> + 1 = 5  ==>  <em>c</em> = 4

<em>d</em> + 1 = 11  ==>  <em>d</em> = 10

Now substitute these values into the desired quantity:

(<em>a</em> + <em>b</em> + <em>c</em> + <em>d</em>) <em>a</em> <em>b</em> <em>c</em> <em>d</em> = 72,000

6 0
3 years ago
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