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butalik [34]
3 years ago
6

Use substitution to solve the system of equations. How many solutions are there?

Mathematics
2 answers:
jok3333 [9.3K]3 years ago
8 0

Answer:

a

Step-by-step explanation:

White raven [17]3 years ago
4 0
The answer is “B” no solution
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What is the equation of the midline of the function f(x) = 5.6sin (2.6x - 4.2) - 9.1?
Iteru [2.4K]

Answer:

f(x) = -9.1

Step-by-step explanation:

The midline is set on f(x) = -9.1, when the sine function is equal to zero, eliminating the effect from amplitude. The midline is a horizontal line. Hence, the equation of the midline is:

f(x) = -9.1

5 0
3 years ago
HELP PLEASE!!!! FASTT
Veronika [31]

Answer:

Domain (-3,-2,-1,0,1,2)

Range (-2,0,1,2,3)

This is not a function

Step-by-step explanation:

Domain (-3,-2,-1,0,1,2)

Range (-2,0,1,2,3)

one x-value with two y-values, (-1, 2) and (-1, -2)

not a function

Plotting the graph should be easy

left side are x-values

right side are y-values

4 0
2 years ago
A rocket is launched straight up from the ground with an initial velocity of 192 feet per second. The equation for the height of
Ivenika [448]

The equation for the height of the rocket at time t given

h= -16t^2+192t

We have to find the time t, when the rocket reaches 560 feet.

That means we have to find t when h = 560 ft. we will place 560 in the place of h to find t now.

h= -16t^2+192t

560 = -16t^2+192t

In the right side, we can check -16 is the common factor. So we will take out -16 from the rigbht side.

560 = -16(t^2 - 12t)

To get rid of -16 from the right side and move it to left side, we will divide both sides by -16.

560/-16 = -16(t^2-12t)/-16

-35 = t^2 -12t

Now we will move -35 to the righ side by adding 35 to both sides.

-35+35 = t^2-12t+35

0 = t^2 -12t+35

t^2-12t+35 = 0

We will factorize thee left side to find the values of t now. We need to find a pair of factors of 35 that by adding them we will get -12.

The pair of factors of 35 are -5 and -7 and by adding -5-7 we will get -12.

t^2-12t+35 =0

(t-5)(t-7) =0

So by using zero product property we will get

t-5 =0

t-5+5 = 0+5

t=5

Also t-7 =0

t-7+7 = 0+7

t=7

So we have got the rocket reaches at 560ft when t = 5 seconds and also when t = 7 seconds.

Now part b.

When the rocket completes its trajectory and hits the ground then the height or h = 0. So we will place h = 0 there in the equation.

h= -16t^2+192t

0= -16t^2 + 192 t

0 = -16(t^2-12t)

-16(t^2-12t) = 0

We will move -16 to the other side by dividing it to both sides.

-16(t^2-12t)/-16 = 0/-16

t^2-12t = 0

We will take out the common factor t from the left side. By taking out t we will get,

t(t-12) = 0

We will use zero product property now. By using that we will get,

t = 0

ans also t-12 = 0

t-12+12 = 0+12

t = 12

When the rocket completes its trajectory and hits the ground the time t can not be 0. When t =0, the rocket starts the trajectory.

So when the rocket completes its trajectory and hits the ground ,

then t = 12seconds.

So we have got the required answers.

6 0
3 years ago
Consider the solution to the linear equation. 5 (x + 6) = 50. 5 x + 30 = 50. 5 x = 20. x = 4. Which describes the inverse operat
dem82 [27]

(trying to isolate/get x by itself in the equation)

5(x + 6) = 50      Distributive property   [distribute 5 into (x + 6)]

5x + 30 = 50    Subtraction    [subtract 30 on both sides of the equation]

5x = 20       Division     [divide 5 on both sides]

x = 4

Subtraction then division, the 2nd option

7 0
3 years ago
Read 2 more answers
Select ALL the expressions that are equivalent to -4(8x-3)
Vinvika [58]

Answer:

dddddStep-by-step explanation:

8 0
3 years ago
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