<span>D: a line passing through the points (2, –6) and (4, –16)</span>
Answer:
Sheila have 6 bills
Step-by-step explanation:
Suppose Sheila has x '20' dollar bills, so the total cost of her bill = $20x
Suppose Tamsin has y '10' dollar bills, so the total cost of her bill = $10y
<h3>Equation 1</h3>
<em>Sheila has a total of $50 more than Tamsin</em>
<h2><em>10y + 50 = 20x</em></h2><h2 /><h3>
Equation 2</h3>
<em>Tamsin has 1 more bill than Sheila.</em>
<h2>y = x + 1 </h2><h2 />
<em>Now solve them by putting value of x in equation </em>
10( x + 1 ) + 50 = 20x
10x + 10 + 50 = 20x
60 = 20x - 10x
10x = 60
x = 60/10
x = 6
and
y = 7
<em> </em>
Answer:
<h2>There is 8% probability of Kitzen winning first and Ava second.</h2>
Step-by-step explanation:
The given table shows that there are 4 students, so there are 4 possible winner in total, but they have different number of tickets.
The total number of tickets is 48, that's the total possible outcomes. Kitzen has a probability of

Ava has a probability of

Now, the probability of having one event and the other is

Therefore, there is 8% probability of Kitzen winning first and Ava second.
(Notice that the probaility is not about Kitzen or Ava winning, it's about winning both, that's why the percentage is low)
Answer:
B
Step-by-step explanation:
because its B hehehehehw
18 times
Since there only two numbers greater than 4 (5 & 6), you subtract 2 from 6.

Then, you divide that from 72.

So, the number of times I would expect the outcome to be greater than 4 is 18.