Answer:
If 4 students travelled in cars, then 341 - 5 = 336students travelled by bus.
There were 5 buses. 336÷ 6 = 56
There were 56 students on each bus.
After the construction of a circle, we have to "Set the compass to the radius of the circle" so, option C is correct.
<h3>What is a regular hexagon?</h3>
A regular hexagon is defined as a closed shape consisting of six equal sides and six equal angles. The sum of the measure of angles of a regular hexagon is 120 degrees.
Steps to create an inscribed hexagon:
1: The structure needs to adjust the box thickness towards that radius.
2: Afterward moves around the outside of the circular path to just produce the 6 vertices of that similar hexagon.
"Set the compass to the radius of the circle" so, option C is correct.
Thus the above answer is correct.
Learn more about inscribed hexagons here:
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H=-t^2+95
The y intercept here is 95, and it represented from where the boy threw the ball.
If he threw it from 95 ft above the ground, the best answer for where he is is on a bridge.
His backyard is at 0 ft (sea level). An underground cave is below sea level. A ladder is probably not 95 ft.
Final answer: D
Complete question is;
Andrea is given ABC and told that a² + b² = c². She draws right triangle RTS with legs measuring a and b and hypotenuse measuring 2. Which best describes what Andrea should
do in order to prove that ABC is a right triangle?
Answer:
Andrea should show that c = 2, so: ∡ABC = ∡RTS and ∡C = ∡S. Hence, ∡C is a right angled triangle, hence ΔABC is a right triangle
Step-by-step explanation:
In this question, we are told that the given sides of the triangle are a, b and c. Now, Andrea is able to draw the two sides of the right triangle with sides = a and b and the third, hypotenuse equal to 2. Since the length of the hypotenuse = 2, then we have;
2² = a² + b²
However, we are told that c² = a² + b²
Therefore, c = 2
Hence, Andrea should show that c = 2 so ΔABC = ΔRTS and ∡C = ∡S hence ∡C is a right angled triangle since it is the angle opposite to the hypotenuse c and therefore, ΔABC is a right triangle.
