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rosijanka [135]
3 years ago
8

Which number line shoes the solution to the inequality -2x-3>-11?

Mathematics
1 answer:
djyliett [7]3 years ago
8 0

Answer:

I think the answer is c because the arrow has to pointing positive.

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1. A box contains 10 blue Stickers, 15 red stickers , and 25 orange stickers . A sticker is selected and its color noted. Then i
denis-greek [22]

Answer:

1/25 ; 3/20 ; 3/50

Step-by-step explanation:

Total number of stickers :

(10 + 15 + 25) = 50 stickers

Probability = required outcome / Total possible outcomes

a. Selecting blue and blue stickers

P(First blue) = 10/50 = 1/5

P(second blue) = 10/50 = 1/5

1/5 * 1/5 = 1 / 25

b. Selecting one red sticker and then one orange sticker

P(First red) = 15/50 = 3/10

P(second orange) = 25/50 = 1/2

3/10 * 1/2 = 3 /20

Selecting one red sticker and then one blue sticker

P(First red) = 15/50 = 3/10

P(second blue) = 10/50 = 1/5

3/10 * 1/5 = 3 / 50

4 0
3 years ago
I need help I’ll mark u as brainlest
Minchanka [31]

Answer:

V = 64 in^3

Step-by-step explanation:

The volume of a cube is given by

V = s^3 where s is the side length

V = 4^3

V = 64 in^3

8 0
3 years ago
Read 2 more answers
Determine the graph of the equation y=20(0.8)^x/3.
otez555 [7]

Answer: it is the 4th graph

Step-by-step explanation:

(-3,25)(0,20)(3,16)(6,12.8)

3 0
2 years ago
There are 7 similarly shaped figures in a set. The largest figure is 7 inches tall. Each of the other figures is 1 inch shorter
galben [10]
The first thing we must do for this case is to find the scale factor based on the dimensions of the figures.
 The largest figure is 7 inches tall. Each of the other figures is 1 inch shorter than the next larger figure.
 We have then that the smallest figure has a height of 1 inch.
 The scale factor is:
 k = (smallest figure) / (largest figure) = 1/7
 k = 1/7
 The surface area of the smaller figure is:
 A = k ^ 2 * (A ')
 Where
 A ': surface area of the largest figure.
 Substituting:
 A = (1/7) ^ 2 * (588)
 A = 12 in ^ 2
 Answer:
 
The surface area of the smallest figure is:
 
A = 12 in ^ 2
4 0
4 years ago
If x^3 + 1/x^3 = 110 then find x + 1/x
Svetlanka [38]
Use:(a+b)^3=a^3+3a^2b+3ab^2+b^3\ (*)\\\\x^3+\left(\dfrac{1}{x}\right)^3\\=\underbrace{x^3+3\cdot x^2\cdot\dfrac{1}{x}+3\cdot x\cdot\left(\dfrac{1}{x}\right)^2+\left(\dfrac{1}{x}\right)^3}_{(*)}-3\cdot x^2\cdot\dfrac{1}{x}-3\cdot x\cdot\left(\dfrac{1}{x}\right)^2\\\\=\left(x+\dfrac{1}{x}\right)^3-3x-3\cdot\dfrac{1}{x}=\left(x+\dfrac{1}{x}\right)^3-3\left(x+\dfrac{1}{x}\right)

therefore

x^3+\left(\dfrac{1}{x}\right)^3=110\iff \left(x+\dfrac{1}{x}\right)^3-3\left(x+\dfrac{1}{x}\right)=110\\\\subtitute\ t=x+\dfrac{1}{x}\\\\t^3-3t=110\ \ \ \ |subtract\ 110\ from\ both\ sides\\\\t^3-3t-110=0\\\\t^3-25t+22t-110=0\\\\t(t^2-25)+22(t-5)=0\ \ \ |use\ a^2-b^2=(a-b)(a+b)\\\\t(t-5)(t+5)+22(t-5)=0\\\\(t-5)[t(t+5)+22]=0\iff t-5=0\ or\ \underbrace{t^2+5t+22=0}_{no\ solution}\\\\t=5\iff x+\dfrac{1}{x}=5\\\\Answer:\boxed{x+\dfrac{1}{x}=5}
3 0
4 years ago
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