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sergeinik [125]
3 years ago
6

A right rectangular prism's edge lengths are 4 1 2 inches, 4 inches, and 3 inches. How many unit cubes with edge lengths of 1 3

inch can fit inside the prism?
Mathematics
1 answer:
fgiga [73]3 years ago
7 0

Question:

A right rectangular prism's edge lengths are  4\frac{1}{2} inches, 4 inches, and 3 inches. How many unit cubes with edge lengths of \frac{1}{3} inch can fit inside the prism?

Answer:

1458 cubes with edge lengths of  \frac{1}{3} inch can fit inside the prism.

Step-by-step explanation:

Given:

Dimensions of the rectangular prism = 4\frac{1}{2} inches, 4 inches, and 3 inches

length of  Edge of the cube = \frac{1}{3}

To Find:

Number of unit cubes that can fit inside the prism =?

Solution:

Step 1: Finding the volume of the right rectangular prism

Volume of the right Rectangular prism is = w\times h\times l

where

w = width of theright Rectangular prism

h = height of the right Rectangular prism

l = lenght of the right Rectangular prism

Substituting the values ,

Volume of the right Rectangular prism is = 4\frac{1}{2}\times4\times 3

Volume of the right Rectangular prism is = \frac{9}{2}\times4\times 3

Volume of the right Rectangular prism is = 4.5\times4\times 3

Volume of the right Rectangular prism is = 54 inch^3

Step 2: Finding the volume of the cube

Volume of the cube = (edge)^3

Substituting the  values,

Volume of the cube = ( \frac{1}{3})^3

Volume of the cube = ( \frac{1}{27})

Step 3: Find the number of cube that can fit in the cube.

Number of  cubes = \frac{\text{volume of the right Rectangular prism}}{\text{Volume of the cube}}

Number of  cubes = \frac{54}{\frac{1}{27}}

Number of  cubes = 54\times27

Number of  cubes  =  1458 cubes

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Can you guys help me with this please it suppose to use the synthetic substitution or the remainder theorem.
Brilliant_brown [7]

9514 1404 393

Answer:

  (b)  -36

Step-by-step explanation:

Synthetic division is often performed using a table of the kind shown in the attachment. The coefficients of f(x) are placed across the top, and the x-value to be evaluated is placed at the left. The rule for finding table entries is shown. (The first (left-most) number at the bottom is the leading coefficient of the polynomial.)

This table shows the remainder, which is f(-2), is -36.

__

The equation itself can be rewritten in "Horner form" to facilitate evaluation.

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  = (22)(-2) +8

  = -36

  f(-2) = -36 . . . . remainder from synthetic substitution

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