Answer:
f(x) = −6(x + 1)(x + 5)
Step-by-step explanation:
f(x) = −6(x + 1)(x + 5) & f(x) = −5(x + 1)(x + 5) are the only ones on the correct side of the y-axis, and f(x) = −6(x + 1)(x + 5) has a y-intercept of -30.
Answer: Hey man, go with your guess, you might be wrong you might be correct.
Step-by-step explanation: But I wouldn't pick or because if you're saying or, you're basically asking the question to the original question so I would pick one of the and's
The remaining number of flires that Linda still not posted is 40.
According to the given question.
The total number of fliers Linda have = 84
Fraction of fliers Linda posted = 1/3
And, fraction of fliers Linda posted second time from the remaning fliers = 2/7
Now,
1/3 of 84 fliers = 1/3 × 84 = 28
So, the number of fliers are left with Linda after first posting = 84 - 28 = 56
Again she posted 2/7 fliers. The number of flires Linda posted second time is given by
⇒ 2/7 × 56 = 16
Thereore, the number of fliers that Lindna still not posted = 56 - 16 = 40
Hence, Linda still not posted 40 fliers.
Find out more information about fraction and remaining numbers here:
brainly.com/question/2254581
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Answer:
Valume of cylinder : πr² × h = π × 5² × 15 = 375π ≈ 1177.5 cm³
Answer: 912
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Work Shown:
The starting term is a1 = 3. The common difference is d = 5 (since we add 5 to each term to get the next term). The nth term formula is
an = a1+d(n-1)
an = 3+5(n-1)
an = 3+5n-5
an = 5n-2
Plug n = 19 into the formula to find the 19th term
an = 5n-2
a19 = 5*19-2
a19 = 95-2
a19 = 93
Add the first and nineteenth terms (a1 = 3 and a19 = 93) to get a1+a19 = 3+93 = 96
Multiply this by n/2 = 19/2 = 9.5 to get the final answer
96*9.5 = 912
I used the formula
Sn = (n/2)*(a1 + an)
where you add the first term (a1) to the nth term (an), then multiply by n/2
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As a check, here are the 19 terms listed out and added up. We get 912 like expected.
3+8+13+18 +23+28+33+38 +43+48+53+58 +63+68+73+78 +83+88+93 = 912
There are 19 values being added up in that equation above. I used spaces to help group the values (groups of four; except the last group which is 3 values) so it's a bit more readable.
