Question

The sum of 3 consecutive odd integers is 7 less than 4 times the largest number. Find all 3 #’s plz show work

Answer 1

Answer:

The integers are -3, -1 and +1.

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Step-by-step explanation:

Let the first integer is X

=> the other two consecutive odd integers are X+2 and X+4

Now we have given that their sum is 7 less than 4 times the largest number

$i.e. \\ x + (x + 2) + (x + 4) = 4(x + 4) - 7 \\ = > \: 3x + 6 = 4x + 16 - 7 \\ = > 4x - 3x = - 16 + 7 + 6 \\ = > x = - 3$

Thus the first integer is -3

the second is (-3+2) = -1

and the third integer is (-3+4) = +1

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If any confusion, please comment.

Answer 2

-3, -1, and 1
-3 - 1 + 1 = -3
4*1= 4
4 - 7 = -3