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erastova [34]
4 years ago
9

Hideki found the solution for the equation below to be r = 66. 6(5 + r) = 96 What mistake did Hideki make in solving the equatio

n? What is the correct solution?
A. He did not distribute 6 to r; r = 11.
B. He did not divide both sides by 6; r = 16.
C. He did not multiply both sides by 6; r = 571.
D. He did not subtract 5 from both sides; r = 15.
Mathematics
2 answers:
alexgriva [62]4 years ago
8 0
6(5 + r) = 96
30 + 6r = 96
6r = 96 - 30
6r = 66
r = 66/6
r = 11

A. He did not distribute 6 to r ; r = 11
cricket20 [7]4 years ago
5 0
Multiplying out 6(5+r) = 96 and solving for r:  30 + 6r = 96

Then 6r = 66, and r = 11.

Answer A is correct.
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Find the domain for the rational function f of x equals quantity x plus 1 end quantity divided by quantity x minus 2 end quantit
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Answer:

(−∞, 2)∪(2, ∞)

Step-by-step explanation:

Domain is all the values that "x" can be

since finding all the values which "x" can be is too hard we will find out the values which "x" can't be- this means equating the denominator to "0" so that the function will be undetermined:

f(x)=\frac{x+1}{x-2}

since we need the denominator to be "0" we must use the opposite of (-2) which is "2" so we will substitute "2" in the place of "x"f(2)=\frac{2+1}{2-2}- the function is now "undetermined" since nothing can be divided by 0 we need to write our answer in proper  domain/range format

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3 years ago
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Derive the equation of the parabola with a focus at (0, 1) and a directrix of y = −1.
mihalych1998 [28]
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(x-0)^2=4(1)(y-0)
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Find the slope-intercept form of the equation of the line that passes through the points AND graph
Rom4ik [11]

Answer: y= 3/5x 6.8

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3 0
3 years ago
Help me with these please​
olchik [2.2K]

Step-by-step explanation:

(1) y = x e^(x²)

Take derivative with respect to x:

dy/dx = x (e^(x²) 2x) + e^(x²)

dy/dx = 2x² e^(x²) + e^(x²)

dy/dx = (2x² + 1) e^(x²)

Take derivative with respect to x again:

d²y/dx² = (2x² + 1) (e^(x²) 2x) + (4x) e^(x²)

d²y/dx² = (4x³ + 2x) e^(x²) + 4x e^(x²)

d²y/dx² = (4x³ + 6x) e^(x²)

Substitute:

d²y/dx² − 2x dy/dx − 4y

= (4x³ + 6x) e^(x²) − 2x (2x² + 1) e^(x²) − 4x e^(x²)

= 4x³ + 6x − 2x (2x² + 1) − 4x

= 4x³ + 6x − 4x³ − 2x − 4x

= 0

(2) y = sin⁻¹(√x)

sin y = √x

sin²y = x

Take derivative with respect to x:

2 sin y cos y dy/dx = 1

sin(2y) dy/dx = 1

dy/dx = csc(2y)

Take derivative with respect to x again:

d²y/dx² = -csc(2y) cot(2y) 2 dy/dx

d²y/dx² = -2 csc²(2y) cot(2y)

Substitute:

2x (1 − x) d²y/dx² + (1 − 2x) dy/dx

= 2 sin²y (1 − sin²y) (-2 csc²(2y) cot(2y)) + (1 − 2 sin²y) csc(2y)

Use power reduction formula:

= (1 − cos(2y)) (1 − ½ (1 − cos(2y))) (-2 csc²(2y) cot(2y)) + (1 − (1 − cos(2y))) csc(2y)

= (1 − cos(2y)) (1 − ½ + ½ cos(2y)) (-2 csc²(2y) cot(2y)) + cos(2y) csc(2y)

= (1 − cos(2y)) (½ + ½ cos(2y)) (-2 csc²(2y) cot(2y)) + cot(2y)

= (cos(2y) − 1) (1 + cos(2y)) csc²(2y) cot(2y) + cot(2y)

= (cos²(2y) − 1) csc²(2y) cot(2y) + cot(2y)

= -sin²(2y) csc²(2y) cot(2y) + cot(2y)

= -cot(2y) + cot(2y)

= 0

8 0
3 years ago
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