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erastova [34]
4 years ago
9

Hideki found the solution for the equation below to be r = 66. 6(5 + r) = 96 What mistake did Hideki make in solving the equatio

n? What is the correct solution?
A. He did not distribute 6 to r; r = 11.
B. He did not divide both sides by 6; r = 16.
C. He did not multiply both sides by 6; r = 571.
D. He did not subtract 5 from both sides; r = 15.
Mathematics
2 answers:
alexgriva [62]4 years ago
8 0
6(5 + r) = 96
30 + 6r = 96
6r = 96 - 30
6r = 66
r = 66/6
r = 11

A. He did not distribute 6 to r ; r = 11
cricket20 [7]4 years ago
5 0
Multiplying out 6(5+r) = 96 and solving for r:  30 + 6r = 96

Then 6r = 66, and r = 11.

Answer A is correct.
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6 0
3 years ago
Read 2 more answers
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OLEGan [10]

Answer:

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v) \frac{BD}{DC}  =  \frac{BD}{3\hspace{0.1cm}cm}  = tan(35) = 0.6128      ∴ BD  = 3 \times 0.6128 = 1.84 cm

vi) ∴ sin(∠ BAD ) = \frac{BD}{AD}      ⇒     sin(∠ BAD ) = \frac{1.84}{9} = 0.2044

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4 years ago
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