Answer:
x = -4
Step-by-step explanation:
3x + 5 = x - 3
Subtract x from each side
3x+5-x = x-3-x
2x+5 = -3
Subtract 5 from each side
2x+5-5 = -3-5
2x = -8
Divide each side by 2
2x/2 = -8/2
x = -4
Answer:
0.000064 = 0.0064% probability that the box will contain less than the advertised weight of 466 g.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean 
and standard deviation 
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
N(489,6)
This means that 
What is the probability that the box will contain less than the advertised weight of 466 g?
This is the p-value of Z when X = 466. So
has a p-value of 0.000064
0.000064 = 0.0064% probability that the box will contain less than the advertised weight of 466 g.
Answer: Step 1 box= 19 (2+3+4+5+5)
Step 2 box= 3.8 (19 divided by 5)
Step-by-step explanation:
You add together the numbers to get 19, the you divide the number by five because you added 5 numbers together.
You had it just right on the bottom. Your equation was perfect. It doesn't matter if you get a decimal number.
Your answers are right too, I double checked.
Hope I was helpful.
Y=foot
x=foram
A. easy, plug 17 for x and evaluage for y
y=0.860(17)+3.302
y=14.62+3.302
y=17.922 inches
B. rate of change is slope
y=mx+b
m=slope
so
rate or change is 0.860 inches per legnth of forarm
C. what data
D. it is a function
since it is 1st degree (no exponents greater than 1 on the placeholder), and it is not a vertical line
it is a function
Answer:
Claim : men weigh of wild jackalopes is 69.9
The null hypothesis : H0 : μ = 69.9
Alternative hypothesis : H1 : μ ≠ 69.9
Test statistic = −2.447085
P value = 0.0174
Conclusion :
Fail to Reject the Null hypothesis
Step-by-step explanation:
From the question given :
The claim is that : mean weight of wild jackalopes is still the same as 10 years with a mean weight of 69.9 lbs.
The null hypothesis : H0 : μ = 69.9
Alternative hypothesis : H1 : μ ≠ 69.9
Using calculator :
Sample mean (x) = 66
Sample standard deviation (s) = 12.345
The test statistic t :
(x - μ) / (s/√n)
n = sample size = 60
(66 - 69.9) / (12.345 / √60)
t = −2.447085
P value at α 0.01, df = 59 is 0.0174
Since the p value is > 0.01, the result is not significant at 0.01. Therefore, we fail to reject the Null
