Area of rectangle=30•12=360 square meters
Area of semicircle=3.14•15•15=353.25 square meters
360+353.25=713.25 square meters
We know that
[lateral surface area of a regular triangular pyramid]=3*[area of one <span>equilateral triangle]
so
[area of one </span>equilateral triangle]=lateral surface/3-----> 81/3-----> 27 ft²
[<span>surface area of the regular triangular pyramid]=lateral area+area of the base
area of the base is equals to the area of the lateral sides because are </span>equilateral triangles
therefore
area of the base=27 ft²
[surface area of the regular triangular pyramid]=81+27----> 108 ft²
the answer is
<span>the surface area of the regular triangular pyramid is 108 ft</span>²
Answer:
According to SSS (side, side, side)
Step-by-step explanation:
Hope it helps...
....
Us the is over of method
50.4•100=5,040
5,040/280=x
X= 18
